The first person has a choice of 6 seats, the second one has only 5 choices, the third one 4 choices, the fourth one 3 choices, the fifth one 2 choices a, and the sixth person has to take the one seat that is left.
So the answer is 6! or 6x5x4x3x2x1 = 720 ways.
In a line, in 6 ways. Around a table, in 2 ways.
720
give 2 ways of presenting data
In a line: 32*31*30 = 29760 In a circle (eg around a table): 29760/3 = 9920.
Chair-#1 can seat any one of 7 people. For each of those . . .Chair-#2 can seat any one of the remaining 6 people. For each of those . . .Chair-#3 can seat any one of the remaining 5 people.Total number of ways to fill the 3 chairs = ( 7 x 6 x 5) = 210
In a line, in 6 ways. Around a table, in 2 ways.
There are many ways in which you could greet a guest. You could always greet a guest with a simple hello.
In how many ways can five children sit at round table?
Hunt seat, saddle seat, bareback, sidesaddle, western. that's all i can think of.
thousands times
There are many ways to sign the guest book at a wedding. Most write a small note of congratulations and then sign their name.
6 i think
There are a great many ways in which you could repair a small burn in your car seat. You could patch it.
6 different ways
students can be seated in 16 diffrent ways. multiply or draw a table. * * * * * Unfortunately, that is an incorrect answer. The correct answer is 4*3*2*1 = 24 ways. For the first seat, on the left, you can pick any one of the 4 students. For the next seat, you have only three students so you have 3 choices. So the number of ways of filling the first two seats is 4*3. Continue the process.
7!
yes