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Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.
It is 1/16.
The probability is 1/4
Mean = 2. Variance = 1.
What is the question?
Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.
It is 5/32 = 0.15625
It is 0.3125
It is 1/16.
The probability is 1/4
In three tosses there can be four possible outcomes: three heads, three tails, two heads and one tail, and one head and two tails. ^^^That is wrongA coin is tossed N times. There are 2 possibilities when you toss a coin: heads and tails.So the formula is 2^N (thats to the N power)A coin tossed 3 times has 2^3=8 possible outcomes:head head headhead head tailhead tail headtail head headtail tail headhead tail tailtail head tailtail tail tailThere they are!
Mean = 2. Variance = 1.
What is the question?
The probability of a fair coin to land head is 1/2. Since for 4 flips it must land heads each time, the probability of 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16.
The odds of each coin toss are 50-50. The coin has no memory; there is no record of what the last four tosses are. EVERY toss is at 50-50 odds.
With 4 coins you have 24 (16) possibilities. If we wanted a specific coin to land 'tails' while the others landed 'heads' we would have one possibilty out of 16. Since we don't care which of the coins lands 'tails,' we have four chances in 16 or a 25 percent chance.
P(H and H and H and H)= 1/2 X 1/2 X 1/2 X 1/2 = 1/16