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Other Dimensions was created in 1970.
It is still an inequality but not a new inequality. It will not alter the existence or non-existence of a solution to a system of linear equations / inequalities.
It is a rectangle which is similar to (but smaller than) the rectangular base.
Two equal size right angle triangles.
FIRST, measure the bottom half. (Measure A) SECOND, measure a STRAIGHT verticle line from top to bottom. (Measure B) Multiply A by B. This works because it can be turned into a rectangle or square. First, make a sraight verticle line starting from the left hand bottom corner. Go up until you meet the upper line. The triangle you have just created should fit into the space that is unoccupied to make a square/rectangle. Hope this helped! . okay, that didnt help. because the poor person up there, probably my reincarnation, SAID ITS NOT A SQUARE OR A RECTANGLE. like all sides uneven, pretty retarded looking excuse for a shape. your wrongggggggggggggg and i need help. rawr.
Discourse on Inequality was created in 1754.
Perimeter Bicycling was created in 1986.
Perimeter Mall was created in 1971.
Libertarianism without inequality was created on 2003-07-03.
An Essay on the Inequality of the Human Races was created in 1855.
Synthetic Dimensions was created in 1985.
Dimensions of Dialogue was created in 1982.
Other Dimensions was created in 1970.
Perimeter E-Security was created in 1997.
Georgia Perimeter College was created in 1958.
New Dimensions was created in 1978-10.
The clever person might realize that, though an infinite number of rectangles can be created with a fixed perimeter, there is a maximum and minimum area that any rectangle formed under the constriction can have. And we can work with that. The minimum area will be "near" zero. (With an area "at" zero, the rectangle will collapse and/or disappear.) The rectangle with "maximumized" area for a fixed perimeter will be a square. Its side (designated by "s") will be one fourth of the perimeter (designated by "p"). If s = p/4 and we use the formula for finding the area (As) of a square substituing our "p/4" for the side length "s" we will get the equation: As = (p/4)2 Our rectangle(s) will all have an area (Ar) within this range: Zero is less than Ar which is less than or equal to (p/4)2 Though we couldn't come up with a precise answer, we came up with the next best thing with the information supplied.