No.
The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
The four consecutive integers with the sum of -66 are -18, -17, -16 and -15.
The sum of the first four non-negative, consecutive, even integers is 20.
If n is the smallest of the four integers, their sum is 4n+6.
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
They are odd consecutive integers: 21, 23, 25 and 27.
There are four consecutive odd integers: 81, 83, 85 and 87.
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
The integers are 21, 22, 23 and 24.
The integers are 51, 53, 55 and 57.
The integers are 5, 6, 7 and 8.
The integers are 6, 7, 8 and 9.
The numbers are 51, 53, 55 and 57.
The sum of two consecutive integers will always be an odd number.
This is impossible with positive integers. However, four numbers separated by a difference of 1 with a sum of -92 are: -21.5 -22.5 -23.5 -24.5
The numbers are 82, 84, 86 and 88.
The integers are -92, -91, -90 and -89.
The integers are 3, 4, 5 and 6.
The integers are 26, 27, 28 and 29.
27 + 28 + 29 + 30 = 114
The integers are 17, 19, 21 and 23.
The integers are -2, 0, 2 and 4.
There is no set of three consecutive integers whose sum is 71.
There is no set of three consecutive integers whose sum is 88.
The answer to that question is 6,7,8,9.
There are no two consecutive integers that sum to 58. With two consecutive integers, one is even, the other is odd. The sum of an even number and an odd number is odd. 58 is even so cannot be the sum of two consecutive integers.