0
No because I divisible by 2.
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What is 3i in mathematics?
The "i" in 3i means the number is imaginary.
Which number can you square that gives an answer smaller than the number thought of?
3i where i is the square root of negative one.3i x 3i = -9
What is the conjugate of 84 minus 63i?
The conjugate of (84-3i) is (84+3i). This gives you a real number when multiplied.
What is the multiplicative inverse of 4 plus 3i?
Use the rules of division for complex numbers. Just divide 1 / (4 + 3i). This requires multiplying numerator and denominator of this fraction by (4 - 3i), to get a real number in the denominator.
What is the conjugate of -3i?
0 + 3i
What is 3i in mathematics?
The "i" in 3i means the number is imaginary.
Is 3i an irrational number?
No. It is an imaginary (or complex) number.
Which number can you square that gives an answer smaller than the number thought of?
3i where i is the square root of negative one.3i x 3i = -9
What is complex conjugate for the number 9-5i?
The conjugate is 7 - 3i is 7 + 3i.
What is complex conjugate for the number 7 3i?
[7 - 3i] To find the conjugate: the sign of the real part stays the same, and the sign of the imaginary part is reversed. So the conjugate of [7 + 3i] is [7 - 3i]
What is complex conjugate for the number 7-3i?
[7 - 3i] To find the conjugate: the sign of the real part stays the same, and the sign of the imaginary part is reversed. So the conjugate of [7 + 3i] is [7 - 3i]
What is the conjugate of 84 minus 63i?
The conjugate of (84-3i) is (84+3i). This gives you a real number when multiplied.
What is the additive inverse of the complex number 8 plus 3i?
To form the additive inverse, negate all parts of the complex number → 8 + 3i → -8 - 3i The sum of a number and its additive inverse is 0: (8 + 3i) + (-8 - 3i) = (8 + -8) + (3 + -3)i = (8 - 8) + (3 - 3)i = 0 + 0i = 0.
What is the factor of 3x2 2x 2 equals 0?
3x2 + 2x + 2 = 0 Can not be factored. You can however solve it for x: 3x2 + 2x = -2 x2 + 2x/3 = -2/3 x2 + 2x/3 + 1/9 = -2/3 + 1/9 (x + 1/9)2 = -5/9 x + 1/9 = ±√(-5/9) x = -1/9 ± i√(5/9) x = -1/9 ± i√5 / 3 x = -1/9 ± 3i√5 / 9 x = (-1 ± 3i√5) / 9
What is conjugate of 2 plus 3i?
- 2 - 3i
What is the multiplicative inverse of 4 plus 3i?
Use the rules of division for complex numbers. Just divide 1 / (4 + 3i). This requires multiplying numerator and denominator of this fraction by (4 - 3i), to get a real number in the denominator.
How do you factor out 16x to the fourth power minus 81?
The answer below does find one root, and finding roots is one way to discover factors. But it does not find the complete factorization. x = -3/2 is also a root of the stated 'equation'. So two of the factors are (2x - 3) and (2x + 3). Then long division could be used to find remaining factor(s).Recall that a2 - b2 = (a + b)(a - b). Let a2 = 16x4, and b2 = 81.so, a = 4x2 and b = 9.So: 16x4 - 81 = (4x2 + 9)(4x2 - 9), and (4x2 - 9) factors to (2x + 3)(2x - 3).So the factorization is: (4x2 + 9)(2x + 3)(2x - 3).With complex: (2x + 3i)(2x - 3i)(2x + 3)(2x - 3), where i = sqrt(-1)So the other two roots are: 3i/2 and -3i/2Finding a root:16X^4 - 81 = 0add 81 to each side : 16X^4 = 81divide both sides by 16, leave as fractionX^4 = 81/16take 4th root both sidesX = 4root(81/16)this can be expressed as.........X = 4root(81)/4root(16)X = 3/2 [indicates (2x - 3) is one of the factors]check16(3/2)^4 - 81 = 016 * 81/16 - 81 = 00 = 0checks
