no, because it should be a segment .
no
yes
Yes.
a polygon is convex
The proof of this theorem is by contradiction. Suppose for convex sets S and T there are elements a and b such that a and b both belong to S∩T, i.e., a belongs to S and T and b belongs to S and T and there is a point c on the straight line between a and b that does not belong to S∩T. This would mean that c does not belong to one of the sets S or T or both. For whichever set c does not belong to this is a contradiction of that set's convexity, contrary to assumption. Thus no such c and a and b can exist and hence S∩T is convex.
the union of two convex sets need not be a convex set.
no
6
Yes...convex mirror diverges light ray that is parallel to the principle axis. The reflected light ray when traced backwards appears to be diverging from principal focus.
yes
A mirror does not refract light, it REFLECTS it.
A mild convex right thoracic scoliosis is when the spine is curved toward the right. It can be seen on an x-ray of the spine.
The answer depends on how it is halved. If the plane is divided in two by a step graph (a zig-zag line) then it will not be a convex set.
A convex polygon is one with no reflex angles (angles that measure more than 180 degrees when viewed from inside the polygon). More generally a convex set is on where a straight line between any two points in the set lies completely within the set.
Yes.
A mild convex right thoracic scoliosis is when the spine is curved toward the right. It can be seen on an x-ray of the spine.
It can be if the set consists of convex shapes, for example.