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No.

sqrt(2)/pi is not rational.

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Q: Is an irrational number divided by an irrational number always a rational?
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Related questions

When an irrational number is divided by a rational number is the quotient rational or irrational?

Irrational.


What happens when a rational number is divided by an irrational number?

When a rational numbers is divided by an irrational number, the answer is irrational for every non-zero rational number.


Is the product of a rational number and irrational number always rational?

No.A rational times an irrational is never rational. It is always irrational.


Can An irrational number divided by an irrational number equals a rational number?

Yes. Any irrational number can be divided by itself to produce 1, which is a rational number.


Is the sum of a rational and irrational number rational or irrational?

It is always irrational.


Is the product of a nonzero rational number and an irrational number rational or irrational?

It is always irrational.


When you multiply an irrational number by a rational number will the answer always be irrational rational or both?

It will be irrational.


Can you multiply an irrational number by a rational number and the answer is rational?

The product of an irrational number and a rational number, both nonzero, is always irrational


What is the product of rational and irrational number?

The product of a rational and irrational number can be rational if the rational is 0. Otherwise it is always irrational.


Is the product of a rational number and an irrational number rational or irrational?

Such a product is always irrational - unless the rational number happens to be zero.


Can you add irrational number and a rational to get a rational number?

If an irrational number is added to, (or multiplied by) a rational number, the result will always be an irrational number.


Is the product of a rational number and an irrational number always irrational?

No. 0 is a rational number and the product of 0 and any irrational number will be 0, a rational. Otherwise, though, the product will always be irrational.