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Answered 2017-03-04 19:00:38

It is neither. If you repeated sets of 8 tosses and compared the number of times you got 6 heads as opposed to other outcomes, it would comprise proper experimental probability.


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Probability of not 8 heads = 1- Prob of 8 heads. Prob of 8 heads = 0.5^8 = 0.003906 Prob of not 8 heads= 1- 0.003906 = 0.99604

The probability of flipping a heads is 1/2 and the probability of rolling a 6 is 1/6. By the laws of probability it would be logical to multiply them together, (1/2)(1/6) thus the answer being 1/12 with is roughly eight percent.

Assuming we want two tails exactly, the possible options to get them are: TTH, THT and HTT. They are three choices out of the eight available, which is a probability of 3/8, 0.375 or 37.5%.

The probability of rolling a four on an eight sided octahedron is 1 in 8, or 0.125.

Probability that it is one of these eight cards is 8/52. Hence the probability of not getting these eight cards is 44/52

Assuming the numbers are 1-6, the probability is 0.

The probability is 61.538 if you are starting with a fresh deck and it is the first draw.

The probability of getting exactly seven tails if you flip a coin eight times is: P(7T1H) = 8∙(1/2)8 =0.03125 ≈ 3.1%

Assuming that there are an equal number of even and odd faces on the eight-sided die, then the probability of rolling an even number is simply 4 in 8, or 1 in 2, or 0.5.

The probability of obtaining 7 heads in eight flips of a coin is:P(7H) = 8(1/2)8 = 0.03125 = 3.1%

I believe it's 4/8 or 1/2 and the probability of the even number is 4/8 also.

Number of cards in a deck =52 Number of cards that are spade =13 Number of cards that are eight =4 Number of cards that are spade and eight =1 Probability that the card drawn is a spade or an eight = 13/52+4/52 -1/52 =16/52 or 4/13

I'm assuming that a "1-8 spinner" is similar to an eight-sided die, so the probability of spinning a 10 is zero. When throwing dice, or flipping a coin, etc., each outcome is independent. That is, it's not influenced by the previous outcome(s). So if you get three 8s in a row then the probability of getting an 8 on the fourth throw remains at 1/8. The probability of an 8 on each and every throw is always 1/8.

There are 4 eight cards, and 12 face cards including the Jack, Queen and King.So 4 +12 =16, which is the number of eight and face cards you have in a standard deck.To find the probability, we will have 16/52 = 0.308

One roll of one normal cube: the answer is 0.

One hundred percent it you toss the coin eight times.

The probability histogram consists of eight bars, labeled '1' through '8', each bar having a value (height) of 0.125 .

For any particular card, (eg an 8) there are 4 such cards in a pack of 52. So the probability of drawing one of these is 4/52, or 1 in 13. After restoring the card to the pack and doing it again the probability is a further 1/13. So the overall probability of doing the 2 things in succession is 1/13 x 1/13 = 1/169.

The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256

Since there are 3 prime numbers, 13, 17, and 19, in the range 12 to 19, the probability of throwing a prime number on a fair eight sided die numbered 12 to 19 is 3 in 8.

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