No, but it is imaginary: 2i.
It is rational.
No. It's +4 and -4.
It's irrational/not a real number
No, an irrational number is, in simple terms, a number that keeps repeating. The square root of 4 is positive or negative 2, which does not repeat and is therefore rational.
[ square root of (4.1) ] is irrational. But [ square root of (4) ] is rational.
The square root of -4 is not irrational, it is imaginary. Irrational numbers are numbers that cannot be expressed as a fraction, like the square root of 2. Irrational numbers, however, are a subset of real numbers. The square root of -4 however, is not even a real number because no real number, when squared, gives -4. Therefore the square root of -4 is an imaginary number.In calculus, the root is expressed as 2i where iis the square root of -1.
Sometimes it is and sometimes it isn't. The square root of 2 and the square root of 3 are both irrational, as is their product, the square root of 6. The square root of 2 and the square root of 8 are both irrational, but their product, the square root of 16, is rational (in fact, it equals 4).
It is rational. The root of a perfect square, such as 4, is rational; the root of any positive integer that is not a perfect square is an irrational number.
There is no square root of negative 8, negative numbers can never be square rooted since no two of the same number can go into a negative number, for example 16's square root is 4 and -4 since 4x4=16 and -4x-4=16, but -16 doesn't have a square root since -4 just turns into a positive when multiplied to itself.
The square root of 4 is 2 which is a rational number
No, the square root is 4 so that means it is rational because it can be turned into a fraction!
The square root of 16 is 4, which is a rational number.