L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.
L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W
30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15 L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.
L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W
30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15
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The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
width=15 length=35
twice length + twice width = perimeter In this example, L= 3W 2(3W)+2(W)=64 8W=64 W=6 L =3W L=18 The dimensions of this rectangle are: 18 by 6
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The dimensions of the rectangle are 21 units by 9 units
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
width=15 length=35
4cm by 13cm
twice length + twice width = perimeter In this example, L= 3W 2(3W)+2(W)=64 8W=64 W=6 L =3W L=18 The dimensions of this rectangle are: 18 by 6
The perimeter of a rectangle is twice the sum of the width and length: perimeter = 2 x (4.6in + 12.1 in) = 33.4 in
Area is length times width, perimeter is twice the sum of length and breadth.
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
15m wide and 31m long