The relevant equation behind this problem is
Q=m*c* ΔT
Where Q is the energy that must be added to or taken from the system, m is the mass of the object, c is the objects specific heat, and ΔT is the change in temperature in Celsius or Kelvin. Plugging in the given values we get that
Q=.015kg * 128J/(kg*C) * 10C=19.2J.
Therefore, you need 19.2 joules of heat in order to raise the temperature of a .015kg sample of lead by 10 degrees Celsius.
50
19.2
.09
19.2