The vertex angle of an isosceles triangle is the angle opposite the base of the triangle. Therefore, the other two remaining angles of the triangle are congruent. so, in this problem: Let x = m of angle B Let x1 = m of angle C Let 3x + 20 = m of angle A x + x + 3x + 20 = 180 5x + 20 = 180 5x = 160 x = 32 degrees Since angle B and C are congruent, the measure of angle C = 32 degrees.
Each base angle is 62.5 degrees
63
44 degrees
If it is an isosceles triangle then the base angles must be equal angles of 69 degrees because there are 180 degrees in a triangle and 42+69+69 = 180 degrees
Vertex angle: 180-42-42 = 96 degrees
(180 - 38)/2 = 71 degrees (base angles of an isosceles triangle are congruent).
63 degrees
57.5 degrees
84 degrees
84 degrees
The vertex angle of an isosceles triangle is equal to the measure of each of its base angles. Therefore, if one of the base angles measures 42 degrees, then the vertex angle also measures 42 degrees.
80 degrees.
If your "53" is in degrees, then the vertex angle is 74 degrees.
40 degrees each
130 degrees is the measure of the base angles of an isosceles triangle whose vertex has a measure of 50 degrees.
Its 2 equal base angles will each measure 65 degrees
Each base angle is 62.5 degrees