The prime numbers (factors) of 120 are: 2,3,5
The prime numbers (factors) of 120 are: 2,3,5
120 is not a prime and no prime numbers equal a composite (ie non-prime).
Three. The prime numbers (factors) of 120 are: 2,3,5
120 = 2*2*2*3*5, so there is 5 prime numbers, no 2 prime numbers
There are 5 prime numbers from 100 to 120:101, 103, 107, 109 and 113
There are 5 prime numbers between 100 and 120: 101 103 107 109 113.
The five prime numbers between 100 and 120 are:101, 103, 107, 109, 113
The prime numbers between 101 and 120 inclusive are: 101, 103, 107, 109, 113
The prime numbers between 90 to 120:= 97, 101, 103, 107, 109 and 113
113 is one of the prime numbers between 100 and 120.
Start by listing out all pairs of numbers greater than 0 and less than or equal to 120 that have a product equal to 120:120 = 1 x 120120 = 2 x 60120 = 3 x 40120 = 4 x 30120 = 5 x 24120 = 6 x 20120 = 8 x 15120 = 10 x 12So, there are 8 factor pairs of 120. Now, show the prime factorization for 120 by expressing it as the product of ALL prime numbers:120 = 2 x 60 Next step is to reduce 60 to the product of prime numbers: 60 = 3 x 20 Next step is to reduce 20 to the product of prime numbers: 20 = 5 x 4 Next step is to reduce 4 to the product of prime numbers: 4 = 2 x 2 The final step is to reduce 2 to the product of prime numbers:So, the prime factorization is as follows: 120 = 2 x 2 x 2 x 3 x 5
The Prime Factors of 120 are: 2 x 2 x 2 x 3 x 5
No. Two even numbers cannot be relatively prime.
There is only 1 and it is the prime 113.
They are: 97+23 = 120 or 2*2*2*3*5 = 120
The numbers 127, 131, 137, 139, 149, 151 and 157 are prime.
120*1div2*2div3*4div5=32
They are: 2*2*2*3*5 = 120
113 is the only prime number in that range.
If it's right, the numbers will all be prime and multiply to 120. 2 x 2 x 2 x 3 x 5 = 120
The prime numbers between 100 and 200 are 101, 103, 107, 109, and 113.
No, they're both divisible by three
2 x 2 x 2 x 3 x 5 = 120