What is 1 percent of glucose crenation or hemolysis?
40% Molecular weight of glucose = 180 Weight of carbon atoms in 1 mole of glucose = 72 weight % of carbon in glucose = 72*100/180
Dissolve 100 g glucose in 1 L distilled water (or 10 g glucose in 100 mL disitlled water).
What is the result of diffusion and osmosis through nonliving membranes of sac 1 containing 40 percent glucose suspended in distilled water?
The glucose was able to go through the sac. The glucose went from high concentration to low concentration. The glucose is permeable.
5.00% mass/volume glucose = 5.00 g glucose / 100 mL solution 5.00 g C6H12O6 x (1 mole C6H12O6 / 180.2 g C6H12O6) = 0.0277 moles glucose M glucose = moles / L = (0.0277 / 0.100) = 0.277 M
I hope you don't work in a hospital, and I also hope you have passed 7th grade. But, 5% of a 1 L (1000 g) solution would be 50 grams.
What would happen if 1 percent glucose is added rather than the amount specified in the recipe for the KIA?
If you added more glucose that the Kliger Iron Agar test than is called for you risk getting false results. The bacteria need to exhaust the glucose to turn the solution red or yellow. If too much glucose is present you may not be able to determine if the bacteria can ferment animal proteins.
The chemical composition of a banana is more complex then most people think. The banana is 75 percent water, 12 percent sugars (glucose, fructose, and maltose), 3 percent fiber, 3 percent amino acids, and 1 percent fatty acids. The fruit also include natural coloring such as Riboflavin for its yellow coloring.
glucose 1 mole has 180,156 grams and has 6.022 x 1023 atoms carbon 1 mole has 12,01 grams and has 6.022 x 1023 atoms. There are 6 carbon atoms in a glucose molecule so that times six would give you a total of 72,06 grams out of the 180,156. Carbon makes up about 40 percent of the total glucose mass so the final answer would be it would be around 2.4088 x 1023 atoms of… Read More
1% (presumably m/v) glucose solution would contain 1 g of glucose per 100 ml of solution. Therefore the conversion of 1 g / 100 ml to units of mol/L requires that we divide by the molar mass and multiply by the conversion factor of ml to L. Therefore: (1 g / 100 ml) * (1 mol / 180.16 g) * (1000 ml / 1 L) = 0.0555 M = 0.06 M.
-first calculate the relative molecular mass (RMM) of glucose 12(6)+1(12)+16(6)= 180 -then the RMM of 6 molecules of carbon 12x6=72 - calculate the percentage 72/180= 0.4 and multiply by 100 to get 40%
1 mole has 12.01 grams and has 6.022 x 1023 atoms. There are 6 carbon atoms in a glucose molecule so that times six would give you a total of 72.06 grams out of the 180.156 (molar mass for glucose). Carbon makes up about 40 percent of the total glucose mass so the final answer would be it would be around 2.4088 x 1023 atoms of carbon in one gram. Times that by 4 and… Read More
1 molecule of glucose is 1 mole of glucose. So .6 moles = .6 molecules
Glucose is C6H12O6. 1 mol of glucose is 6 mol of carbon, 12 mol of hydrogen, and 6 mol of oxygen. 1 mol Glucose x (6 mol C / 1 mol Glucose) = 6 mol C
Glucose is a NON-ELECTROLYTE. Since it doesn't dissociate to give ions in a solvent such as water. Since glucose dissolves as intact molecule in water therefore on dissolving 1 mole of glucose in 1 L water we should get 1 molar solution of glucose.
1. increase the number of glucose carriers 2. increase glucose concentration
No, Maltose is made up from the combination of two glucose . While, combining 1 glucose with 1 fructose gives sucrose .
A 1 molar solution is a solution in which 1 mole of a compound is dissolved in a total volume of 1 litre. formula weight of glucose is 180.2 - measure 180.2 g of glucose into a graduated cylinder, then add water until the final volume is equal to 1 L If you dissolve 180.2g of glucose in a final volume of 1 litre, you have made a 1M glucose solution.
The molecular formula of glucose is C6H12O6. 1 mole glucose = 6.022 x 1023 molecules. 1 molecule glucose = 24 atoms 1mole glucose x 6.022 x 1023 molecules/mole x 24 atoms/molecule = 1 x 1025 atoms (rounded to 1 significant figure)
Blood glucose is monitored with blood glucose testing meter.
what is the weight of a cup of glucose syrup.
1 glucose molecule = approx. 0,3.10-21 g
1 molecule of glucose is C6H12O6 and so has 24 atoms
1 glucose can be broken down into 2 pyruvates. hence, 2 pyruvates equal to one glucose.
You need to dissolve 180 grams of glucose in water and make it up to 1000ml. this produces 1 M Glucose solution.
They form different disaccharides due to there molecular structures. Alpha forms Maltose with a 1-4 glycosidic bond between each alpha glucose and another, and Beta forms the disaccharide Cellobiose with a 1-4 glycosidic bond between each beta glucose and another.
The reducing end of a carbohydrate is found at the anomeric carbon. For glucose, this would be Carbon #1 (C-1).
2. (1)glucose --> (2)Carbon dioxide + (2) Ethanol + (2) ATP aerobic on the other hand produces 38 Atp per glucose molecule. (1) glucose + (6) oxygen---> (6) oxygen + (1) water + (38) atp
Glucose is broken down in the first stage of respiration- glycolysis where it is phosphorylated by a molecule of ATP to form 1-6 glucose phosphate. It is then isomerised ti
Alpha and beta glucose differ only in the direction that -H and -OH groups point on carbon 1 (labelled). Alpha glucose has an -OH group that points "downwards", away from the ring, whereas the -OH on carbon 1 of beta glucose is in line with the ring.
Answer 1 Glucose syrup is sugar, used in lollies and other sweet things. Adding glucose to your food instead of using a sweetener, is bad for you. Sweeteners are a better choice than glucose and normal sugar.
1 glucose:2 ATP
1. Cellulose - beta glucose 2. Starch - aplha glucose
The answer is 90,08 g glucose.
i know it's higher than corresponding blood glucose concentration from 10 - 15%
1M glucose means that 1 mole of glucose is dissolved in 1kg of water. Since 1M means 1 molal. And molality is equla to no.of moles of solute per kg of water.
The molecular weight of free glucose is 180.2 while that of glucose in glycogen is 160 explain this anomaly with structural diagrams?
Put the following glucose solutions in order of least concentrated (A) to most concentrated (E) (note: mw of glucose is 180)10 grams glucose in 75 millilitres of water600 mM glucose5 mg in 1 mL water7.5 mM glucose in 10 mM NaCl10 % (w/v) glucose
1% of glucose- no color changes 1% sucrose-no color changes 1% xyxlose-black 1%starch-light white 1%lactose-black
1 percent of a percent is 1/10000 or 0.0001; this is the same as saying 1 percent percent. Example: 5 percent percent is 0.0005, so 5 percent percent of 100 is 0.0005 x 100 or 0.05.
1 percent is less than 25 percent. 1 percent is greater than 0.25 percent.
glucose and fructose form same osazone crystals because carbon no 1 to carbon no 6 are identical both in glucose and in fructose
Molarity = moles of solute/Liters of solution So, we need moles of glucose. 4 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.02220 moles glucose --------------------------------------------------------------------------------------------------- Molarity = 0.02220 moles C6H12O6/1 Liter = 0.02 M glucose ----------------------
Yes, .1 percent is a tenth of 1 percent.
No 5 percent is five times 1 percent just a 5 is 5 times 1. Half of 1 percent is 0.5 percent.
Cellulose is a biopolymer that is built by beta 1, 6 linkage between the glucose residues. The molecule that resembles it most closely is chitin that has N acetylglucosamine, that is the glucose aminocylated at 2' carbon. In hemicellulose, there is a backbone of glucose and there are side chains of some other glucose residues. Starch and glycogen are also made up of the glucose residues but they are linked by alpha 1-4 linkage.
GLUT1 is a passive protein transport. Glucose with GLUT1 can only be transported from high to low concentration. With the sodium - glucose symporter it's possible to transport glucose from low to high concentration.
in glucose it is carbon# 1... and in fructose it is carbon# 2... becoz aldehyde and ketone group of glucose and fructose are attached to ist and 2nd carbon respectivally....
2 ATP are produced per 1 glucose molecule
Typically, "sweet" corn is roughly 9-14% glucose and other sugars. The highest concentrations of sugars in corn is in the "supersweet" hybrid that tops out around 44% concentrations of sugars. Field corn usually has less than 1% sugar.
P. aeruginosa is not alpha hemolytic. Hemolysis is used mainly for the identification of Streptococci and can be used for Staphylococci. P. aeruginosa can be mistaken for being alpha hemolytic because it produces a green diffusable pigment. This pigment is especially visible if grown in media with little to no pH dye indicators such as SIM tubes, nutrient broths (undisturbed), API strips, etc. A good way to tell the difference between diffusable pigment production and… Read More
0.29% 29 percent of 1 percent: = 29% of 1% = 29% * 1% = 0.29 * 1% = 0.29%