# What is 56 out of 60 as a percentage?

%rate:

= (56/60) x 100%

= 0.9333 x 100%

= 93.33%

### What is the angular speed of a particle performing 56 RPM along a circle?

56 rpm = 56 rotations per 60 secs. Ï‰ = 2Ï€/T (from http://blade3891.tripod.com/id9.html) Ï‰ is the angular velocity. T is the period. This is the number of seconds it takes to complete one rotation. Since it takes 60 seconds to complete 56 rotations, it takes 60/56 seconds to complete one rotation. T = 60/56. so Ï‰ = 2Ï€/(60/56) = roughly 5.86 radians per second