b benefits
If a number is pure imaginary then it has no real component. If it is a real number, then there is no imaginary component. If it has both real and imaginary components, then it is a complex number.
If you are talking about pure imaginary numbers (a complex number with no real part) then no. Example: bi times ci where b and c are real numbers equals b*c*i² = b*c*(-1) = -b*c, which is a real number, because b & c & -1 are all real numbers. If you're talking about multiplying two complex numbers (a + bi)*(c + di), then the product will be complex, but it could be real or imaginary, depending on the values of a, b, c, & d.
When a complex number is multiplied by its conjugate, the product is a real number and the imaginary number disappears.
real
Yes. If you multiply X + iY by X - iY you get X2 + Y2. The imaginary parts cancel out.
It can be either.
Yes it is.
product differentiation
For example, product differentiation might be necessary when a new laundry detergent is advertised.
A company that excels at product differentiation can normally demand a higher price for a product because of its perceived higher quality.
It's an imaginary killer killing imaginary critters, I think it is probably company execs drumming up interest in their product.
The imaginary part is expressed as a product of i(square root of negative one), typically following a plus sign, so that the complex number has the form a + bi, with "a" the real part and "bi" the imaginary part.
Product differentiation is the process of customizing products. When you order food without items that come with the food then the business allows you to differentiate your product.
If a number is pure imaginary then it has no real component. If it is a real number, then there is no imaginary component. If it has both real and imaginary components, then it is a complex number.
Paolo Annunziato has written: 'Pricing practices in markets with product differentiation' -- subject(s): Product differentiation
If you are talking about pure imaginary numbers (a complex number with no real part) then no. Example: bi times ci where b and c are real numbers equals b*c*i² = b*c*(-1) = -b*c, which is a real number, because b & c & -1 are all real numbers. If you're talking about multiplying two complex numbers (a + bi)*(c + di), then the product will be complex, but it could be real or imaginary, depending on the values of a, b, c, & d.
Yes if it was not practical it was not there. You can see the real life use on this link http://www.intmath.com/Applications-differentiation/Applications-of-differentiation-intro.php