Approximately 10 inches.
Approximately 17 feet.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
Using Pythagoras' theorem it is about 4.243 feet rounded to 3 decimal places
The diagonal length is about 18.44 inches.
Using Pythagoras' theorem: 162+122 = 400 and the square root of this is 20 (the diagonal) Therefore: 16+12+20 = a perimeter of 48 inches
Approximately 17 feet.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
The length of the other diagonal works out as 12cm
Using Pythagoras' theorem it is about 4.243 feet rounded to 3 decimal places
The length of one diagonal is not sufficient to determine its sides and so its perimeter.
The diagonal length is about 18.44 inches.
The diagonal length = 7.07 inches.
Using Pythagoras' theorem: 162+122 = 400 and the square root of this is 20 (the diagonal) Therefore: 16+12+20 = a perimeter of 48 inches
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet
The perimeter of this square is 56.569 meters.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.