0
What is the area of a hexagon with a side of 10 inches and an apothem of 8 inches?
Wiki User
∙ 9y ago
The question cannot be answered.
A regular hexagon with sides of 10 inches would have apothems of 10/sqrt(2) = 7.071 inches. Therefore the hexagon cannot be regular.
And, since the hexagon is irregular, there is not enough information to answer the question.
Wiki User
∙ 9y ago
Add your answer:
Earn +20 pts
What is the area of a regular hexagon with apothem length of 24 inches?
For a regular hexagon, half the side length can be calculated from the apothem via trigonometry: half_side_length = apothem x tan 30° Then: area = apothem x 1/2 x perimeter = apothem x 1/2 x side_length x 6 = apothem x half_side_length x 6 = 24 in x (24 in x tan 30°) x 6 ≈ 1995 sq in
What is the apothem of a regular hexagon?
If the hexagon has side length s, then the apothem is sqrt(3) * s / 2.
What is the area of a regular hexagon with a side length of 2 centimeter and an apothem length of 10.4 centimeters?
Such a hexagon is impossible. A regular hexagon with sides of 2 cm can have an apothem of sqrt(3) cm = approx 1.73.It seems you got your question garbled. A regular hexagon, with sides of 2 cm, has an area of 10.4 sq cm. If you used your measurement units properly, you would have noticed that the 10.4 was associated with square units and it had to refer to an area, not a length.
The area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches Find the length of a side of the regular hexagon?
The area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. Find the length of a side of the regular hexagon.Click once to select an item at the bottom of the problem.
How do you find the area of a octagon with only the apothem?
Octagon is composed of 8 triangles, which can be combined in pairs to make 8 rectangles of which one side is the apothem. The area is 1.657 x the square of the apothem, simplified from 4 times the square of the apothem divided by tan67.5o ie 2.4142. 4 divided by 2.4142 is 1.657. Consider triangle OAB where OB is the apothem and AB is half of a side: The angle OAB = 67.5 degrees, half of the interior angle of a regular hexagon. Tan 67.5 = OB/AB so AB = OB/tan 67.5 and the area of each notional rectangle is OB squared divided by tan 67.5. There are four such rectangles hence 4OB2/tan 67.5 is the area of the octagon.
Area of the regular hexagon whose side length is 16 in and apothem is 8 square root 3 in?
It is 665.1 sq inches.
What is the area of a regular hexagon with a perimeter of 36 inches and an apothem of 5.2 inches?
Given the perimeter of a regular hexagon, it is better to use the side length: 6 inches, rather than the apothem of 5.2 inches because the latter is he rounded value of 3*sqrt(3) which is 5.196152... rather than 5.2. Based on the length of the sides, the area is approx 93.53 sq inches. [The apothem would have given 93.67 sq inches.]
What is the area of a regular hexagon whose side lenght is 16 inches and the apothem is 8 square root of 3?
665.1 square units.
What is the area of a regular octagon with a side length of 4 inches and an apothem length of 4.8 inches?
By joining all the vertices to the centre of the octagon, the apothem forms the height of the triangles with the side of the regular octagon as the base. This the area is 8 × area_triangles = 8 × ½ × side × apothem = 4 × side × apothem: Area_regular_octagon = 4 × side_length × apothem ≈ 4 × 4 in × 4.8 in = 76.8 in²
What is the area of a regular hexagon with apothem length of 24 inches?
For a regular hexagon, half the side length can be calculated from the apothem via trigonometry: half_side_length = apothem x tan 30° Then: area = apothem x 1/2 x perimeter = apothem x 1/2 x side_length x 6 = apothem x half_side_length x 6 = 24 in x (24 in x tan 30°) x 6 ≈ 1995 sq in
What is the apothem of a regular hexagon?
If the hexagon has side length s, then the apothem is sqrt(3) * s / 2.
What is the Area of a regular hexagon with a base of 10 and an apothem of 20?
12 x 5 x 20 ie 1200squnits. I'm not convinced you can have such a hexagon, if the side is 10 then shouldn't the apothem have to be 5 root 3?
Find the area of the regular hexagon described in the question above?
Let s be the length of a side of the hexagon and let h be the the apothem 6(1/2sh) it the area of 3sh.
What is the side length of a regular hexagon with area 100 square centimeters?
5.7735026918962... The formula for the area of a hexagon is A=.5ap, or A=(1/2)ap, where A=area, a=apothem, and p=perimeter. This means that, because the area is 100, 100=.5ap, so 200=ap. Because in a regular hexagon the apothem is equal to the side length, what we are really saying here is that 200=6a2. Therefore, 33.333=a2, or a= about 5.77. This is the side length.
What is the perimeter of a hexagon having 225 cm square area of a circle inscribed in it?
Area of circle = 225 cm2 implies radius = 8.46 cm (approx) Therefore, apothem of hexagon = 8.46 cm then side of hexagon = apothem*2/sqrt(3) = 9.77 cm (approx) and so perimeter = 6*side = 58.63 cm
What is the area of a regular hexagon with a side of 4 and an apothem of 3 46?
Easy. Since the side is the base and the apothem is the height of the triangle, multiply them and divide by two to get the area of the triangle. 3 * 3.46 = 10.38 /2 = 5.19. Then multiply by 6 to get the area of the hexagon. 5.19 * 6 = 31.14. You multiply by 6 because you can fit 6 regular triangles in a regular hexagon. We've already found the area of one regular triangle in the hexagon.
What is the apothem of a regular hexagon with sides of 16 inches?
We know that the height of an equilateral triangle equals the product of one half of the side length measure with square root of 3.Since in our regular hexagon we form 6 equilateral triangles with sides length of 16 inches, the apothem length equals to 8√3 inches.
