Using Pythagoras its base works out as 36 and so 36*15 = 540 square units
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
15 cm for the diagonal.
The diagonal is 25 feet.
4,3Improved Answer:-The dimensions work out as: 2.358898944 and 6.358898944 inches using the quadratic equation formula
15 inches (solved with the help of Pythagoras' theorem)
15 units2
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
A 9 x 12 rectangle has a diagonal of 15.
120
15 and 20 inches because these dimensions comply with Pythagoras' theorem and the area of the rectangle.
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The diagonal is about 28.3 feet.
Area = height * width Area = 15 * 30 = 450 square units
120 feet
15 cm for the diagonal.
The diagonal is 25 feet.
The answer is 15 feet. The area of a rectangle is the length times the height. So 25 times what = 375. Divide 375 by 25. This equals 15