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Negative the derivative of f(x), divided by f(x) squared.

-f'(x) / f²(x)

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Q: What is the derivative of 1 divided by fx under the conditions that fx is differentiable and fx cannot be 0?
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Related questions

Where is f(x) discontinuous but not differentiable Explain?

Wherever a function is differentiable, it must also be continuous. The opposite is not true, however. For example, the absolute value function, f(x) =|x|, is not differentiable at x=0 even though it is continuous everywhere.


Why absolute value of x is not differentiable at point 0?

The absolute value of x, |x|, is defined as |x| = x, x>=0; -x, x<0. If you derive this, then you will find that the derivative is 1 when x>=0, and -1 when x<0. But this means that the derivative as x approaches 0 from the left does not equal the derivative as x approaches 0 from the right, as -1=/=1. So the limit as x approaches 0 does not exist, and therefore the gradient does not exist at that point, and so |x| cannot be differentiated at x = 0.


Which cannot be divided?

Zero (0) cannot be divided


What is the derivative of 3x 4?

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals".If the question is about 3x + 4 or 3x - 4, then the answer is 3.


What is water divided by oxygen?

Water cannot be divided by oxygen.


Is there any number that cant be divided?

0 cannot be divided


What can 6 be divided by 91?

0.0659


Can 593 be divisible by 234569 or 10?

No. 234569 is larger than 593 and so 593 cannot be divided by it, and it cannot de divided by 10.


182 divided by 24?

7.5833


How do you find maximum of function?

It depends on the function and the level of your mathematical skills. It also depends on whether you are looking for a global maximum or a local one. For example, a cubic equation [y = ax3 + bx2 + cd + d] has no global maximum but it will usually have a local one. This is also the case for any equation that is asymptotically +infinity somewhere in its domain. If a function is twice differentiable over the domain in question, differentiate it once, set the resulting derivative equal to zero and solve for the coordinates of the stationary point. Next, differentiate it again and evaluate the value of the second derivative at the stationary point. If this derivative is negative, you have a local maximum at the stationary point. But be careful at the edges of the domain. All this does not help if the function is not twice differentiable. Sometimes there are other ways. For example, let P(X = x) be the [probability distribution] function that X, the sum of the numbers on two dice, is x. Then it can easily be shown that P(2) = P(12) = 1/36 P(3) = P(11) = 2/36 P(4) = P(10) = 3/36 P(5) = P(9) = 4/36 P(6) = P(8) = 5/36 P(7) = = 6/36 and P(x) = 0 elsewhere. P is not a continuous function and so cannot be differentiable, but the table above shows that the maximum of the function is at P(7).


What is 0 divided by 1?

Undefined: You cannot divide by zero


What number cannot ever be divided by?

Zero