Top Answer

Conduct the following experiment:

Roll a number cube 50 times.

Count the number of times you roll a 2.

Divide that number by 50.

That is the experimental probability.

The answer that I might get may well be different to yours. And if you do you experiment another time, the answer is likely to be different.

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0The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36

The probability of rolling a number less than 6 on a die would be 5/6.

The probability is 21/36 = 7/12

The probability is 1. It is a certainty that you will roll a number between and including one and six. The probability of rolling each individual number is 1/6.

Because 3/6 of the sides on a number cube have even numbers, the probability of rolling even on one number cube is 1/2(equivalent of 3/6). But since you're rolling twice, you multiply the probability of one by itself (therefore rolling 2 number cubes). So: 1/2x1/2=1/4 The probability of rolling an even number when a number cube is rolled twice is 1/4, 25%, or 1 out of 4.

The probability is 1, if the dice are rolled often enough.

If the die is rolled often enough, the probability is 1. With only two rolls of a fair die, the probability is 1/6.

If you're only rolling one die, it's a probability of 1 out of six, or 16.67%.

When a number cube is rolled twice, there are 36 possible outcomes. (1,1),(1,2),....(6,6). (3,3) occurs only once. Therefore, the probability of rolling a 3 both times is 1/36.

For most people the probability is 1: they have already rolled a number cube. For infants, it is quite likely to happen in the course of their lives, so again the probability is very close to 1.

If the die is rolled often enough, the event is a certainty - probability = 1. For a single roll, the probability is 1/2.

The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.

The probability is 1, if the dice are rolled often enough.

Assuming as the die is rolled, and its a 6-sided die (1, 2, 3, 4, 5, & 6), each number has a 1/6 probability of being rolled. The probability of any number being rolled is 1/6 and the probability of not rolling that number is 5/6. Something that has only 2 outcomes, such as boy & girl or heads & tails, will have the 50 50 probability.

If you rolled 2 fair dice, the probability of having a sum of 6 is 5 over 36

A number cube is a six sided figure so I'm going to go with 0%

The question depends on what the numbers are being rolled on: a hexahedron or some other shape.

That would depend upon what it is that is being rolled.

The probability that the number rolled, on a fair, six sided die, will be greater than 4 is 1/3.The probability that the number rolled, on a fair, six sided die, will be greater than 4 is 1/3.The probability that the number rolled, on a fair, six sided die, will be greater than 4 is 1/3.The probability that the number rolled, on a fair, six sided die, will be greater than 4 is 1/3.

If the number cubes are standard dice cubes, the odds of rolling 3 ones is 1 in 216.

When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.

a 12-sided die is rolled. The set of equally likely outcomes is (1,2,3,4,5,6,7,8,9,10,11,12). What is the probability of rolling an 8

The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.

The answer depends on how often the die is rolled. As the number of rolls increases, the probability gets near enough to 1 as makes no difference. For a single roll, the answer is 1/3.

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