It is 16*sqrt(2) feet.
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
The diagonal of a rectangle is the third and longest side of a triangle with sides the same as those of the rectangle, so its length is the square root of the sum of the squares of the lengths of the sides of the triangle, (Pythoagoras' Theorem) which are also the sides of the rectangle. If the rectangle is 3 inches by 4 inches, then the diagonal is the square root of 3 squared (= 9) and 4 squared (= 16) so the diagonal is the square root of 16 + 9 = 25, giving it the length of 5 inches.
A square with a side length of 16 inches has an area of 256 square inches.
Each side is 4. The diagonal is 5.66 and the area is 16 square units.
48
The side lengths of a square with a diagonal of 16 is: 11.31.
The length of one side of a square with a 16-centimeter diagonal is: 11.31 cm
Using Pythagoras' theorem the diagonal is 16 times the square root of 2
A "regular quadrilateral" is a square. The word "radius" isn't used for squares (or polygons in general). To get the length of a side, divide the perimeter by 4. To get the diagonal of a square, multiply the length of a side by the square root of 2.
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
16*sqrt(2) = 22.627 (to 3 dp).
If the perimeter is 64, then one side is 16. The diagonal is the hypotenuse of a right triangle. Hello Pythagoras. The answer is the square root of 512 or 16 times the square root of 2.
The diagonal of a rectangle is the third and longest side of a triangle with sides the same as those of the rectangle, so its length is the square root of the sum of the squares of the lengths of the sides of the triangle, (Pythoagoras' Theorem) which are also the sides of the rectangle. If the rectangle is 3 inches by 4 inches, then the diagonal is the square root of 3 squared (= 9) and 4 squared (= 16) so the diagonal is the square root of 16 + 9 = 25, giving it the length of 5 inches.
If you take the square of the long side and add it to the square of the short side, you get the diagonal (hypotenuse) squared. Then just find square root of that. For example, if short side is 3cm and long side is 4cm: 9 + 16 = 25, so the diagonal would be the square root of 25 ie. 5.
5.7 ft
A square with a side length of 16 inches has an area of 256 square inches.
Each side is 4. The diagonal is 5.66 and the area is 16 square units.