End points: (3.2, 2.5) and (1.6, -4.5)
Midpoint: ( 2.4, -1)
End points: (3, 5) and (7, 7) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Perpendicular bisector equation: y-6 = -2(x-5) => y = -2x+16
Yes, because GB = GR - RB
Midpoint = (6+16)/2 and (6-6)/2 = (11, 0)
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
y = -2x+16 which can be expressed in the form of 2x+y-16 = 0
If you mean endpoints of (16, 5) and (-6, -9) then its midpoint is (5, -2)
End points: (3, 5) and (7, 7) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Perpendicular bisector equation: y-6 = -2(x-5) => y = -2x+16
Yes, while naming a line segment, as long as the two points are on the line, it does not matter what order they are in or which points they are. well their not
midpoint between 4-16
midpoint between 4-16
Yes, because GB = GR - RB
Midpoint = (6+16)/2 and (6-6)/2 = (11, 0)
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
17.5
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
y = -2x+16 which can be expressed in the form of 2x+y-16 = 0