A set with 27 members has 2^27 = 134217728 subsets - including itself and the null set.
I believe the number of subsets for a set is equal to 2 raised to the power of the size of the set, so this set would have 27 = 128.
It has 27 = 128 subsets.
There are infinitely many subsets of real numbers. For example, {2, sqrt(27), -9.37} is one subset.
Think about it - this one is fairly simple. Ask yourself the question: "Does this set have a largest element?" If the answer is "yes", then the set is finite. If the answer is "no", the set is infinite. Note: This reasoning works for subsets of natural numbers; for integers, additional adjustments are needed.
It belongs to many many subsets including: {sqrt(13)}, The set of square roots of integers The set of square roots of primes The set of square roots of numbers between 12 and 27 {3, -9, sqrt(13)} The set of irrational numbers The set of real numbers
-27 is one possible answer.
This is not possible, 27 is an odd number, 4 odd numbers will always equal an even number.
Anything from zero to 26 .
-9x = 27 x = -3 The solution set contains only one value for x, -3, which is just a point on the number line 3 units to the left of zero.
Each number is 3 times greater than the previous number
No, 27 is not a prime number. 3x9 = 27
I think you mean range. To find the range of a set of data, subtract the lowest number from the highest number. Example: 45 78 92 27 34 18 Higest Number: 92 Lowest Number: 18 92 - 18 = 74