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1m and 11m 2m and 10m 3m and 9m 4m and 8m 5m and 7m. The next one, 6m and 6m, would be a square.
Prime factors of 55 are 5 and 11, which differ by 6, so length 11m, width 5m!
11 m
1100
11m + 13 = m + 23 10m + 13 = 23 10m = 10 m = 1
32m
The diagonal would be 12.53 meters.
11x5 m is 32m
well if you add it it is easy. A:11m.The above is a load of bovine droppings. P = 2(L + W) so the CORRECT answer is 22 m.The perimeter of a rectangle is 2 x (length + width).2 x (7m + 4m) = 2 x 11m = 22m
if the perimeter is 46m, then side + length = 23 so we need two values, when added together are 23, with a difference of 11 6 + 17 = 23, (and have a difference of 11) therefore the length = 17m, width = 6m
1m and 11m 2m and 10m 3m and 9m 4m and 8m 5m and 7m. The next one, 6m and 6m, would be a square.
The Area of a rectangle is calculated by multiplying the length by the width. For a pool with a length of 26m and a width of 11m, you can then calculate the area simply by multiplying these two values together:Area = 26 x 11 = 271m^2
If the room is square, its area is 11m X 11m = 121 square meters.
11m = 0.011km
Prime factors of 55 are 5 and 11, which differ by 6, so length 11m, width 5m!
11m + 4n - 3m +11n = 8m + 15n
You need to know the dimensions of the room to determine the cost. Remember the room COULD be 121M x 1M, or 11M x 11M, for example. Without the dimensions the perimeter could be many different values.