22 meters
The perimeter (distance around the outside) = length + width + length + width
P = 2L + 2W
2 (4) + 2 (7) = 22
28meters
well if you add it it is easy. A:11m.The above is a load of bovine droppings. P = 2(L + W) so the CORRECT answer is 22 m.The perimeter of a rectangle is 2 x (length + width).2 x (7m + 4m) = 2 x 11m = 22m
(4 + 1) × 2 = 10 metres
Perimeter=2(l+b) =2*6 =12m
28 square meters
24 meters Perimeter (distance around the outside) = two lengths and two widths P = 2L + 2W 2 (7) + 2(5) = 24
well if you add it it is easy. A:11m.The above is a load of bovine droppings. P = 2(L + W) so the CORRECT answer is 22 m.The perimeter of a rectangle is 2 x (length + width).2 x (7m + 4m) = 2 x 11m = 22m
Rectangle with area 28 m2 and width = 4 m => length = 28/4 = 7m. Then, perimeter = 2*(4+7) = 2*11 = 22 metres.
(4 + 1) × 2 = 10 metres
The area of rectangle is : 56.0
Perimeter = 2*(4m + 85cm) = 2*4.85 m = 9.7 m
7*8*4 = 224 cubic metres.
(4 + 1) × 2 = 10 metres
Perimeter=2(l+b) =2*6 =12m
1m and 11m 2m and 10m 3m and 9m 4m and 8m 5m and 7m. The next one, 6m and 6m, would be a square.
um i think you multiply them
In order to make sense of this question it is necessary to assume that the area is 28 SQUARE metres and not 28 metres as stated. Then, Length = Area/Width = 28/4 = 7m Then perimeter = 2*(Length + width) = 2*(7 + 4) = 2*11 = 22 metres.
28 square meters