Geometry

# What is the perimeter of a rectangle with a length of 9.5 yards and a width of 4 yards?

It is: 2*(9.5+4) = 27 yards

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## Related Questions

the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?

The length is 200 yards and the width is 48 yards.length + width = 248 yards, and length = (4 x width) + 8 yards.substituting (4 x width) + 8 yards for length,(4 x width) + 8 yards + width = 248 yards;simplifying, width = 240/5 yards = 48 yards;then length = 248 - 48 yards = 200 yards

The perimeter is the total distance around - width + width+ length + length.

If those are the dimensions of a rectangle then its perimeter is 2*(5+3)=16 yards

The rectangle would have two sides with 5 yards length and two sides with 3 yards of width, so you would have 5*2 + 3*2 = 10 + 6 = 16 yards.

None. 42 yards is a length with no width. Therefore it cannot have a perimeter.

So it has 2 sides of 5 and 2 sides of 3 yards so the perimeter is 5 + 5 + 3 + 3 = 16 yards

Its area is: 7 times 8 = 56 square yards Its perimeter is: 7+8+7+8 = 30 yards

Perimeter = 2*(L+W) = 2*(3+7) = 2*10 = 20 yards. By the way, conventionally, the length is the bigger dimension.

Perimeter is the length round the outside. A basketball court is a rectangle, so: perimeter = 2 x (length + width) = 2 x (30 yd + 40 yd) = 2 x 70 yd = 140 yd

I assume 202 yards is the perimeter. It really depends on the shape of the figure - whether it is a square, rectangle, circle, elipse, etc. In the case of a rectangle, for example, this would also depend on the length to width ratio. In summary, different figures have different perimeters for the same area (or different areas for the same perimeter).I assume 202 yards is the perimeter. It really depends on the shape of the figure - whether it is a square, rectangle, circle, elipse, etc. In the case of a rectangle, for example, this would also depend on the length to width ratio. In summary, different figures have different perimeters for the same area (or different areas for the same perimeter).I assume 202 yards is the perimeter. It really depends on the shape of the figure - whether it is a square, rectangle, circle, elipse, etc. In the case of a rectangle, for example, this would also depend on the length to width ratio. In summary, different figures have different perimeters for the same area (or different areas for the same perimeter).I assume 202 yards is the perimeter. It really depends on the shape of the figure - whether it is a square, rectangle, circle, elipse, etc. In the case of a rectangle, for example, this would also depend on the length to width ratio. In summary, different figures have different perimeters for the same area (or different areas for the same perimeter).

It could be: length 3 yards and width 54 yards, OR length 6 yards and Width 27 yards. All you have to do is think of it this way: If the area is 162 square yards, what two numbers multiplied together equal 162?

Assuming that you have a rectangle shaped area, 20 yards long by 15 yards wide, and you want to completely enclose the area with the fencing, then you have a problem where you need to find the perimeter of a rectangle. Perimeter = 2 * Length + 2 * Width Perimeter = 2 * (20 yd) + 2 * (15 yd) = 40 yd + 30 yd = 70 yards

If the perimeter is 346 and the length is 67 yards longer then the width.Then346 = 2x + 2(x+67) = 4x + 1344x = 212x = 53The width is 53 yards53 + 67 = 120The length is 120 yardsTo check 120 + 53 + 120 + 53 = 346

Length + width = &frac12; perimeter, ie 42 yards or 126 feet. L = 6 W so w = 126/7 = 18 feet and length is 108 feet ie 36 yards.

4.5 yardsArea = Length * Width58.5 = 13 * w58.5/13 = 13w/1358.5/13 = w4.5 = wthus, width = 4.5 yards

"12 yards" is not an area. I must assume that you meant to saythat the area is 12 square yards.Then the length is 4 yards.

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