Perimeter = 2*(L + W)= 2*(45 + 32) = 2*77 = 154 cm.
8 length 8 width
Perimeter = 2*(7+9) = 32 units.
32 cm
w= widthw+4=length2(w+l)= perimeter2(w+w+4)=32 substitution2(2w+4)=324w+8=32 distributive property4w=32-8 subtraction property of equality4w=24w=6 division property of equalitylength is 6+4 or 10cm.
6
8 length 8 width
32 cm
Length + width = half of perimeter ie 36.7 in. If length is 4.7 in then width is 32 in.
7 feet
I think you mean the width is 6. The answer depends entirely on what the length of the rectangle is. For example, if it is a square, so that the length and width are both 6, the answer is 24. I the length is 10, the perimeter is 32. In general, just add the width (6) to the length and double the sum to get the perimeter.
Perimeter = 2*(7+9) = 32 units.
Perimeter = 32 inches. Area = 55 square inches.
They will be both the same because the perimeter of the square is 32 units and the perimeter of the rectangle is also 32 units
Let the width be x feet. Then, the length would be (x+7) feet. Given that decreasing the length by 3 feet and increasing the width by 2 feet gives a perimeter of 32 feet, you can set up the equation 2( (x+7) - 3 + x + 2) = 32 to find the original width x and length (x+7).
It is: 2(32+56) = 176 feet
32 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (9) + 2 (7) = 18 + 14 = 32 also: P = 2 (L + W) 2(9 + 7) = 32
32