It is 16 units.
27
56 (: When we say polygon abcd is similar to polygon afge, they already told you which are the lines that are similar. ab:af=bc:fg=cd:ge etc. Lines ad and af are not similar in length and therefore cannot be used to find perimeter of polygon abcd even though the perimeter of polygon afge is given.
Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?
10
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
27
If abcd is a parallelogram, then the lengths ab and ad are sufficient. The perimeter is 36 units.
56 (: When we say polygon abcd is similar to polygon afge, they already told you which are the lines that are similar. ab:af=bc:fg=cd:ge etc. Lines ad and af are not similar in length and therefore cannot be used to find perimeter of polygon abcd even though the perimeter of polygon afge is given.
A+=14 * * * * * Not sure what the above answer means. But whatever it is, it is not the correct answer to this question! ae is half of ad so the second figure has the linear dimensions of the second are half that of the first. Therefore, the perimeter is half ie 27 units.
Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?
10
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
14
Isosceles trapezoid ABCD has an area of 276 If AD = 13 inches and DE = 12 inches, find AB.
28.00
10
you multiply 2 times the width and 2 times the length ad then add them together. the equation would be 2l+2w=perimeter