15 out of 49
The probability is 15/49.
Assuming then that there are 100 numbers, 1-100, the probability of the number 23 being randomly picked out of 100 is: 1/100 or 0.01.
There are 15 primes from 1 to 49 (including '1').The probability is (15/49) = 30.612 %(rounded)
Since 49 is a composite, the answer is 0.
Prime numbers from 1 to 15 are: 2 3 5 7 11 and 13 So the probability is: 6/15 or as 2/5
The chances of picking a number between 2 to 5 is 4/10 if the numbers to be picked from are 1-10. However, if the numbers to be picked from are 1-100, then the probability drops to 4/100.
The probability of a prime number in a random pick from the numbers 1-49 is 15 in 49, as there are 15 prime numbers (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43,and 47) in the range of 1 to 49.
If they are randomly picked, each 5-number combination is equally likely. If the long-term results of any lottery show that any number or combination is more likely than others, then the game is not honest.
If the winning numbers are picked at random, the probability is 1 in 169911.
There are 8 out of 20 numbers that are prime, so 8/20, or 2/5.
What is the probability that the letter P is picked when a letter is picked at random from the word STUPID!
Pr(Both picked 3) = 1/16Pr(Both picked the same) = 1/4.
Unless it is a personally requested plate, the numbers and letters are randomly picked by the MVD to identify that particular vehicle.
randomly they were just picked randomly.
53.33... % THere are 8 odd numbers out of 15, so probability = 100*8/15 %
you get randomly picked
she got picked randomly
If a student is picked at random what is the probability that he/she received an A on his/her fina?
If only one person is picked at random then the probability is 1/16 = 0.0625
To work out probability you have to know the number of possible options, and how many of those options meet the criteria. In this case there are 26 possible options (all the letters) and 21 that meet the criteria (21 non-vowels). The probability is the number that match divided by the total number possible. In this case it would be 21/26. This comes out to approximately 0.80769. Thus the probability that a letter picked at random is not a vowel is 0.80769
An interesting question. The answer is 80%. A number must end in 0 or 5 to be dividable by 5. From 100 to 109 (10 numbers in total), there will be 2 numbers that are dividable by 5. If I then consider the entire set from 100 to 999 is 900 numbers, you have 90 sets of 10 numbers, each set with 2 dividable number, or 180/900 = 2/10 =20%. If 20% are dividable, 80% aren't. Suppose I extended the question, and say my set is all whole positive numbers and zero with n digits or less, where I pick n randomly from 1 to a million. If from this set, a number is picked randomly, what is the chance that it is dividable by 5. Answer: 20%.
The probability that a date picked at random is February 30th is zero, as there is no February 30th, even in leap years.
Not sexed. The birds you get are randomly picked.
They are picked randomly out of a hat
The probability of winning a straight lottery of 6 numbers picked from 56 is 1 in 32,468,436.The number of combinations of n things taken m at a time is (n!-m!)/m! so this is 56 * 55 * 54 * 53 * 52 * 51 / 6 / 5 / 4 / 3 / 2 / 1 = 32,468,436.