There are 13 diamonds. Three cards are dealt. The probability of all of them being diamond is (13/52)(12/51)(11/50) = 1716/132600 = 11/850
The answer depends on how many cards you are dealt!
hypergeometric distribution: f(k;N,n,m) = f(5;52,13,5)
the percentage chance is 32 and 100
The odds are 220:1 of being dealt pocket aces.
The answer will depend on the exact situation.If you are dealt a single card, the probability of that single card not being a queen is 12/13 - assuming you have no knowledge about the other cards.Here is another example. If you already hold three queens in your hand (and no other cards have been dealt), the probability of the next card being dealt being a queen is 1/49, so the probability of NOT getting a queen is 48/49 - higher than in the previous example.
5
The answer depends on how many cards are dealt out to you - which depends on how many cards you are dealt.
The answer depends on how many cards you are dealt!
If only one card is dealt randomly from a deck of cards, the probability is 1/52.
hypergeometric distribution: f(k;N,n,m) = f(5;52,13,5)
the percentage chance is 32 and 100
The odds are 220:1 of being dealt pocket aces.
The answer will depend on the exact situation.If you are dealt a single card, the probability of that single card not being a queen is 12/13 - assuming you have no knowledge about the other cards.Here is another example. If you already hold three queens in your hand (and no other cards have been dealt), the probability of the next card being dealt being a queen is 1/49, so the probability of NOT getting a queen is 48/49 - higher than in the previous example.
The probability, if the cards are dealt often enough, is 1.On a single deal, the prob is 3.69379*10^-6
The probability of drawing two diamonds from a deck of cards is (13 in 52) times (12 in 51), or 156 in 2,652, or 78 in 1,327.
A 8/52 chance.
There are 13 clubs in a standard deck of 52 cards. The probability, then, of drawing club is 13 in 52, or 1 in 4, or 0.25.