The probability is 1. I have flipped a coin a lot more than 7 times.
If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8
The probability of getting 6 heads and 1 tail when flipping a fair coin 7 times is:7*(1/2)6*(1/2) = 7/128.
each time you flip the coin, probability to end on either side is 50% (or 0.5) (we disregard landing on the side). So, to land on the same side 7 times, it is: 0.5^7
The probability of each coin coming up heads is 1/2 .The probability of all 7 coming up heads is (1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2) = 1/128That's 0.78 percent (rounded)(Dr. Atticus was right.)
It is 8/28 = 1/32 = 0.03125
Okay, lets write out the possible outcomes when flipping a coin 3 times: HHH, HHT, HTH, THH, TTH,THT,HTT,TTT That constitures 8 scenarios in which the coin can fall over a 3 flip trial. Now, it is known that you got "at least one head" so therefore we can rule out the no head scenario (TTT) which leaves us with 7. Of those 7 times, how many times does it fall heads exactly twice? Well, we have HHT,HTH,THH. From this you can say that it there are 3 possible outcomes in which you get exactly two heads given that you get at least one head. 3/7.
Empirical means by observation, so empirical probability, or experimental probability, is the probability that is observed in a set of trials. For example, if you flip a coin ten times and get seven heads, your empirical probability is 7 in 10. This is different than the theoretical probability, which for a fair coin is 5 in 10, but that result will only be approximated by the empirical results, and then only with a larger number of trials.
3/7, but only if the coin is taken at random.
This is easiest calculated by calculating the probability that NO SINGLE heads is obtained; this is of course the complement of the question. The probability of this is 1/2 x 1/2 x 1/2 ... 7 times, in other words, (1/2)7. The complement, the probability that at least one head is obtained, is then of course 1 - (1/2)7, or a bit over 99%.
That's the same as the total probability (1) minus the probability of seven heads. So: 1 - (1/2)7 = 127/128
The probability is that it comes out 7 times out of 10 tries, or 70% of the times.
The experimental probability of a coin landing on heads is 7/ 12. if the coin landed on tails 30 timefind the number of tosses?
The answer would be 7x7x7x7. 2401 to 1.
The probability to get heads once is 1/2 as the coin is fair The probability to get heads twice is 1/2x1/2 The probability to get heads three times is 1/2x1/2x1/2 The probability to get tails once is 1/2 The probability to get tails 5 times is (1/2)5 So the probability to get 3 heads when the coin is tossed 8 times is (1/2)3(1/2)5=(1/2)8 = 1/256 If you read carefully you'll understand that 3 heads and 5 tails has the same probability than any other outcome = 1/256 As the coin is fair, each side has the same probability to appear So the probability to get 3 heads and 5 tails is the same as getting for instance 8 heads or 8 tails or 1 tails and 7 heads, and so on
They are just used to make equations and make more things like more equations and estimates!Theoretical Probability: P(event) the ratio of the number of favorable outcomes to the number of possible outcomes, written as a ratio.example: number of favorable outcomes over number of possible outcomesAmelynn is hungry, so she gets out a bowl and puts in 2 red jelly beans, 3 blue jelly beans, 12 pink jelly beans, and 3 yellow jelly beans. Amelynn likes the pink ones the best. What is the theoretical possibility of her getting a pink jelly bean?Answer: 12 over 20. (or 3 over 5 [simplest form])Explanation: Amelynn put 20 jelly beans in the bowl. She wants the pink ones, andthere are 12 pink jelly beans, which are the favorable outcomes. There are 20 jelly beans, and these are the possible outcomes. This means that it is 12 over 20. You might have to put this in simplest form as well. also this is 60% total.******************************************************************************************Experimental Probability: The number of times the outcome occurs compared to the total number of trials.example: number of favorable outcomes over total number of trials.Amelynn is flipping a coin. She finished the task one time, then did it again. Here are her results: heads: three times and tails: seven times. What is the experimental probability of the coin landing on heads?Answer: 3/10Explanation: Amelynn flipped the coin a total of 10 times, getting heads 3 times. Therefore, the answer is: 3/10 or 30%Theoretical probability ... a coin has 2 sides so the theoretical probability of flipping a coin and getting heads is 1/2.Experimental probability... flip a coin 10 time and you get 7 heads so the experimental probability of getting heads is 7/10
7/8 1-(1/2 x 1/2 x 1/2)
(8!/(6!2!) / 2**8 = 28/256 = 7/64 = 0.109375
7*(1/2)7 = 7/128 = 5.47% approx.
99/512, or 19.34%. The nCr formula can be used in this case: 12!/((12-7!)*7!) ---> 95,040/120 ---> 792 792/(2^12) = 99/512
The probability of Tails on the first toss is 1/2.The probability of Tails on the second toss is 1/2.The probability of Tails on the third toss is 1/2.The probability of Tails on the fourth toss is 1/2.The probability of Tails on the fifth toss is 1/2.The probability of Tails on the sixth toss is 1/2.The probability of Tails on the seventh toss is 1/2.The probability of all of them is (0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5) = (0.5)7 = 0.0078125= 0.78125 %
This is a Binomial Probability Distribution, with number of trials n=7, r = 4, 5, 6, & 7 (at least 4 is 4 or more), and probability p is 1/2 or 0.5. The related link gives the binomial probabilities and the values, which are added together. The values for r = 4, 5, 6, & 7 are 0.273, 0.164, .055, .008. These add to 0.5, so the probability of getting at least 4 heads with a coin tossed 7 times is 0.5 or 50%.
you have 63 chances out of 64. i once witnessed a coin being tossed seven times and giving up 7 consecutive heads. we never tried it an eighth time, 7 heads and you had to go to the bar.
The opposite of getting at most two heads is getting three heads. The probability of getting three heads is (1/2)^2, which is 1/8. The probability of getting at most two heads is then 1 - 1/8 which is 7/8.
The probability of obtaining 7 heads in eight flips of a coin is:P(7H) = 8(1/2)8 = 0.03125 = 3.1%
I'm assuming you are asking what is the probability (P) of flipping a quarter.This answer really depends upon how many times up are going to flip it.If you are flipping it once, you have a 50% chance that it will land on heads and a 50% chance that it will land on tails. Either way the sum of your probabilities will add up to 1, meaning that there is a 100% chance that something will occur (see probability rules).EX: Let H= heads and let T=tails∑P= P(H)+P(T)=0.5+0.5=1However, let's say you were going to flip a coin 3 times and were wanting to know what the probability of getting at least 1 tail was. You would approach the problem this way:P( at least 1 tail)=?Next, you want to find the compliment (the opposite of what you are starting with). So the opposite of getting one tail is getting no tails. This is the same as getting all heads.P(no tails)=P(all heads)P( all heads)= P(H)3 Heads is cubed because you are flipping the coin 3= P(0.5)3 times and want all the outcomes to be heads.= 1/8By knowing that the outcome plus its compliment add up to equal 1 you get:P( all heads) + P( at least 1 tail)=1P( at least 1 tail) = 1- P( all heads)P( at least 1 tail) = 1- 1/8P( at least 1 tail) = 7/8So the probability of flipping a coin 3 times and getting a least 1 tail is 7/8. In other words, it's very likely that it will land on tails one of those three times.