The probability is 1/2 because the second outcome has no affect on the first outcome.
Well, you have 24 possibilities, and you can get heads 6 ways, so it is 1/4.
Your question is a bit difficult to understand. I will rephrase it as follows: What is the probability of getting a head if a coin is flipped once? p = 0.5 What is the probability of getting 2 heads if a coin is flipped twice = The possible events are HT, TH, HH, TT amd all are equally likely. So the probability of HH is 0.25. What is the probability of getting at least on head if the coin is flipped twice. Of the possible events listed above, HT, TH and HH would satisfy the condition of one or more heads, so the probability is 3 x 0.25 = 0.75 or 3/4. Also, since the probability of TT is 0.25, and the probability of all events must sum to 1, then we calculate the probability of one or more heads to be 1-0.25 = 0.75
P(tail) is 0.5. You want P(tail) AND P(tail) = 0.5 * 0.5 = 0.25 or 1/4.
The answer is 1/2 , assuming the coin is fair.
2 out of 3 i think
The probability of this is 50%. 2/4
The probability is 25%. The probability of flipping a coin once and getting heads is 50%. In your example, you get heads twice -- over the course of 2 flips. So there are two 50% probabilities that you need to combine to get the probability for getting two heads in two flips. So turn 50% into a decimal --> 0.5 Multiply the two 50% probabilities together --> 0.5 x 0.5 = 0.25. Therefore, 0.25 or 25% is the probability of flipping a coin twice and getting heads both times.
Well, you have 24 possibilities, and you can get heads 6 ways, so it is 1/4.
Your question is a bit difficult to understand. I will rephrase it as follows: What is the probability of getting a head if a coin is flipped once? p = 0.5 What is the probability of getting 2 heads if a coin is flipped twice = The possible events are HT, TH, HH, TT amd all are equally likely. So the probability of HH is 0.25. What is the probability of getting at least on head if the coin is flipped twice. Of the possible events listed above, HT, TH and HH would satisfy the condition of one or more heads, so the probability is 3 x 0.25 = 0.75 or 3/4. Also, since the probability of TT is 0.25, and the probability of all events must sum to 1, then we calculate the probability of one or more heads to be 1-0.25 = 0.75
P(tail) is 0.5. You want P(tail) AND P(tail) = 0.5 * 0.5 = 0.25 or 1/4.
If you flip a coin twice, there are four possible results:H HH TT HT T.The result you're interested in is one of the four possibilities.So its probability is 1/4 = 25% .
The answer is 1/2 , assuming the coin is fair.
20!/(18!*2!) * (1/2)^20 = 190/1048576 = 0.000181198... So less than 1 in 5000.
The best way to think about this is the following way: What is the probability of flipping heads once? 1/2 What is the probability of flipping heads twice? 1/4 (1/2 * 1/2) Using this we can derive the equation to find the probability of flipping heads any number of times. 1/2n Using this we plug in 25 for n and get 1/225 or as a decimal 2.98023224 x 10-8 or as odds 1:33,554,432
It is 0.25
The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.
2/12 or 1/6