The probability of getting exactly seven tails if you flip a coin eight times is:
P(7T1H) = 8∙(1/2)8 =0.03125 ≈ 3.1%
The probability of obtaining 7 heads in eight flips of a coin is:P(7H) = 8(1/2)8 = 0.03125 = 3.1%
The probability of getting a diamond and a black seven is zero. Diamonds are red.
The probability of getting only one tails is (1/2)7. With seven permutations of which flip is the tails, this gives a probability of: P(six heads in seven flips) = 7*(1/2)7 = 7/128
The requirement that one coin is a head is superfluous and does not matter. The simplified question is "what is the probability of obtaining exactly six heads in seven flips of a coin?"... There are 128 permutations (27) of seven coins, or seven flips of one coin. Of these, there are seven permutations where there are exactly six heads, i.e. where there is only one tail. The probability, then, of tossing six heads in seven coin tosses is 7 in 128, or 0.0546875.
Exactly seven of them can.
It is 1: a certainty. A complete pack of cards must have a seven.
There are four a's in ALABAMA. The probability of choosing an a from a random draw of those seven letters is 4 in 7, or about 0.5714.If you are talking about getting a grade of A from a school in Alabama, that is entirely up to you and to how well you apply yourself.
7*(1/2)7 = 7/128 = 5.47% approx.
Probability of drawing a seven of spades, from a 52 card deck, is 1/52.
I t is necessary to assume thata single card is drawn,it is drawn at random,it is a normal deck of cards.If these assumptions are realised - and there is nothing in the question to suggest that they are - then the probability is 1/52.
Assuming you're drawing from a complete shuffled 54-card deck, chances are one in twenty-seven.
That's the same as the total probability (1) minus the probability of seven heads. So: 1 - (1/2)7 = 127/128
The probability of one event or the other occurring is the probability of one plus the probability of the other. The probability of getting 3 heads is the probability of 3 heads (1/23) multiplied by the probability of 4 tails (1/24) multiplied by the number of possible ways this could happen. This is 7c3 or 35. Thus the probability of 3 heads is 0.2734375. The probability of 2 tails is the probability of 2 tails (1/22) multiplied by the probability of 5 heads (1/25) multiplied by the number of ways this could happen. That is 7c5 or 21. Thus the probability of 2 tails is 0.1640625 The probability of one or the other is the sum of their probabilities: 0.1640625 + 0.2734375 = 0.4375 Thus the probability of getting 3 heads or 2 tails is 0.4375.
The answer will depend on what the trial is!
There are 4 sevens so probability of drawing a seven is 4/52 or 1/13 or 0.0769.
Because seven eight nine
Eight and seven thousandths
7 goes into 28 exactly 4 times, so 7 one quarter of 28. One quarter of a given number is 25%
three, seven, eight, forty, fifty, sixty
That depends on how many dice you use. For example, if you use a single die, the probability is 100%.
Eight was afraid of nine because nine "ate/eight" seven, or afraid of seven because seven eight nine, more common
Eight billion, seven hundred seventy-eight million, eight hundred seventy-seven thousand, seven hundred eighty-eight.
seven to ten hours eight is best
The probability that the sum is seven all three times is 1/216.
What do you mean? LIke for example, if you have a bag with the follow: 888887777775 The probability would be 11/12 666778999999 The probability would be 1/4 (3/12) You take the number in total and that is your denominator(Number on bottom) You take the total number of sevens and eights and that is you numerator(Number on top) Than reduce as needed.
Asked By Wiki User
Asked By Wiki User