The probability of flipping a fair coin four times and getting four heads is 1 in 16, or 0.0625. That is simply the probability of one head (0.5) raised to the power of 4.

If a coin is flipped 4 times, the probability of getting 3 heads is: 4C3 (1/2)^3 (1/2)^1 = 4(1/8)(1/2) = 4/16 = 1/4

The sample space is HH, HT, TH, HH. Since the HH combination can occur once out of four times, the probability that if a coin is flipped twice the probability that both will be heads is 1/4 or 0.25.

The probability that a coin flipped four consecutive times will always land on heads is 1 in 16. Since the events are sequentially unrelated, take the probability of heads in 1 try, 0.5, and raise that to the power of 4... 1 in 24 = 1 in 16

Multiply the probability by the number of times the experiment was carried out. 0.6x10=6

The probability of flipping a coin 3 times and getting 3 heads is 1/2

Probability of not 8 heads = 1- Prob of 8 heads. Prob of 8 heads = 0.5^8 = 0.003906 Prob of not 8 heads= 1- 0.003906 = 0.99604

The opposite of getting at most two heads is getting three heads. The probability of getting three heads is (1/2)^2, which is 1/8. The probability of getting at most two heads is then 1 - 1/8 which is 7/8.

The probability of a flipped coin landing heads or tails will always be 50% either way, no matter how many times you flip it.

The probability of flipping a coin 24 times and getting all heads is less than 1 in 16 million. (.524) It would seem that no one has ever done that.

The probability of getting 3 or more heads in a row, one or more times is 520/1024 = 0.508 Of these, the probability of getting exactly 3 heads in a row, exactly once is 244/1024 = 0.238

you are looking for the probability of getting one tail, two,......., and six this equivalent to saying 1 - the probability of not getting any tails (or getting 6 heads = (1/2)^6). P(X>=1) = 1 - (1/2)^6=

That's the same as the total probability (1) minus the probability of seven heads. So: 1 - (1/2)7 = 127/128

It is neither. If you repeated sets of 8 tosses and compared the number of times you got 6 heads as opposed to other outcomes, it would comprise proper experimental probability.

The correct answer is 1/2. The first two flips do not affect the likelihood that the third flip will be heads (that is, the coin has no "memory" of the previous flips). If you flipped it 100 times and it came up heads each time, the probability of heads on the 101st try would still be 1/2. (Although, if you flipped it 100 times and it came up heads all 100 times - the odds of which are 2^100, or roughly 1 in 1,267,650,000,000,000,000,000,000,000,000 - you should begin to wonder about whether it's a fair coin!). If you were instead asking "What is the probability of flipping a coin three times and having it land on "heads" all three times, then the answer is 1/8.

the probability of getting heads-heads-heads if you toss a coin three times is 1 out of 9.

You still still have a 1:2 chance of getting heads regardless of the times you flip.

Experimental Probability: The number of times the outcome occurs compared to the total number of trials. example: number of favorable outcomes over total number of trials. Amelynn is flipping a coin. She finished the task one time, then did it again. Here are her results: heads: three times and tails: seven times. What is the experimental probability of the coin landing on heads? Answer: 3/10 Explanation: Amelynn flipped the coin a total of 10 times, getting heads 3 times. Therefore, the answer is: 3/10.

The probability of landing on heads at least once is 1 - (1/2)100 = 1 - 7.9*10-31 which is extremely close to 1: that is, the event is virtually a certainty.

The mathematical probability of getting heads is 0.5. 70 heads out of 100 tosses represents a probability of 0.7 which is 40% larger.

1/2 chance of getting heads or tails 5 times 1/10

This is easiest calculated by calculating the probability that NO SINGLE heads is obtained; this is of course the complement of the question. The probability of this is 1/2 x 1/2 x 1/2 ... 7 times, in other words, (1/2)7. The complement, the probability that at least one head is obtained, is then of course 1 - (1/2)7, or a bit over 99%.

They are HHT HTH and THH

For 3 coin flips: 87% chance of getting heads at least once 25% chance of getting heads twice 13% chance of getting heads all three times

Answer this Question : Probability of getting 10 heads in a row is(1/2)^10 = 1/1024 = 0.000976 or 0.098 %

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