There are 15 primes through 50, so it would be:
(15 * 14) / (50 * 49) = 3 / 35
It is 0.4
2, 3 and 5 are prime so P = 0.5
The probability of rolling a prime number on a standard 6-sided die is 3 in 6, or 0.5.The sample space is [1 2 3 4 5 6] and the result space is [2 3 5]. 3 divided by 6 is 0.5.
1/2
With a standard 6 faced die, numbered 1 through 6, there are three odd numbers, 1, 3, and 5, of which 3 and 5 are prime, and there is one even prime, 2. The probability, then, of rolling an odd number which is prime is 1 in 3, i.e. 3 or 5 out of a possible result set of 1, 2, 3, 4, 5, and 6.
If the only numbers to pick from are 1 through 8, how can you get a factor greater than 10?
The probability is 17C4 = 2380
It is 0.4
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.
A spinner has the numbers 1 thru 9. What is the probability of P(less than 6)? Write the answer as a decimal.
There are 20 numbers from 20 through 39, and 4 of them are prime (23, 29, 31, 37), the probability is 4 in 20 or 0.20.
There are 15 primes from 1 to 49 (including '1').The probability is (15/49) = 30.612 %(rounded)
If each of the numbers on the spinner is equally likely, then the answer is 0.3
The probability that the spinner will land on six depends on how many numbers are on the spinner. If the spinner is only 1 through 6, then there is a 16.67% probability that the spinner will land on six with each spin.
Because it is the process of deriving probability through repeated experiments.
It is 0.375
2/3 or 66.667% chance