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There are 11 crayons, so the chance of picking any specific crayon is 1/11. Because four of them are red, the chance of choosing one of the four red crayons is 4/11.

After the first draw, there are 10 crayons remaining, three of which are red (assuming the first crayon drawn was red; if it was some other color, we don't care, because there's then no chance that we will end up with two red crayons). So the chance of drawing a red crayon on the second draw is 3/10.

The overall chance of pulling two red crayons in a row is 4/11 x 3/10, or 12/110 ... a shade under 11 percent.

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7y ago
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7y ago

It is 6/55.

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Q: What is the probability of picking two red crayons if you pick two in a row without replacing the first one from 11 crayons including 4 red 3 yellow and 4 green crayons?
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