These are all independent events (flipping a coin will not affect the probability of drawing a Jack) so you can get the probability of all events occurring by multiplying together the probabilities of each event occurring. In other words: P (4 or 6, 2 heads, Jack) = P(4 or 6) * P(2 Heads) * P(Jack) Now we need to look at each probability separately. Remember that: Probability = Successful Outcomes / (Successful Outcomes + Unsuccessful Outcomes) In the case of rolling a die, a successful outcome (as defined in the problem) is rolling a 4 or 6. An unsuccessful outcome is everything else (1, 2, 3, or 5). Using the formula above then: Probability (4 or 6) = 2/6 = .33 Figuring out the probability of rolling two heads is slightly different because we are talking about two flips not one. In this case we have to go back to our original formula for multiple events. Probability (2 Heads) = Prob(Head) * Prob(Head) Since we know a coin-toss has a 1/2 chance of being heads or tails: Probability (2 Heads) = .5 * .5 = .25 Finally, in the case of picking up a card from a deck, a successful outcome (as defined in the problem) is picking a Jack. There are 4 Jacks in a standard deck so there are 4 possibilities of a successful outcome. There are 48 cards in a stardard deck that are not Jacks. Therefore: Probability (Jack) = 4/52 = .077 Now we can plug these values into our combination formula to get our answer. P (4 or 6, 2 heads, Jack) = P(4 or 6) * P(2 Heads) * P(Jack) P (4 or 6, 2 heads, Jack) = .33 * .25 * .077 = .00635 There is a .635% chance of rolling a 4 or 6, flipping a heads twice, AND drawing a Jack.
The probability of flipping a quarter and getting heads is 1 in 2. the probability of rolling a die and getting 6 is 1 in 6.
It is 0.25
These would be independent events; therefore, we can multiply the probabilities of each of the two events. Probability of flipping a head: 1/2 Probability of rolling an odd number with a single die: 1/6 Required probability : 1/2 x 1/6 = 1/12
The probability of flipping Heads on a coin is 1 - a certainty - if the coin is flipped often enough. On a single toss of a fair coin the probability is 1/2.
The probability of flipping a coin 3 times and getting 3 heads is 1/2
The probability of rolling a 2 on a die before flipping a heads on a coin is 1 in 12. The probability of rolling a 2 is 1 in 6. The probability of flipping heads is 1 in 2. Since these are sequentially unrelated events, you simply multiply the probabilities together.
The probability of flipping a quarter and getting heads is 1 in 2. the probability of rolling a die and getting 6 is 1 in 6.
It is 0.25
a three on a dice is 1/6 and aheads on a coin is 50%
You take the probability of each event and multiply them. In the case of the given example, your odds or flipping a head and rolling a 5 would be 1/2 * 1/6, which equals 1/12.
Multiply together the probability that each event would have of occurring by itself. For example, the probability of rolling a "3" on a single die is 1/6 ,because there are 6 different possibilities. And the probability of flipping a "heads" on a coin is 1/2 , because there are two possibilities. Then the probability of rolling a "3" AND flipping a "heads" is ; 1/6 x 1/2 = 1/12 .
50-50
These would be independent events; therefore, we can multiply the probabilities of each of the two events. Probability of flipping a head: 1/2 Probability of rolling an odd number with a single die: 1/6 Required probability : 1/2 x 1/6 = 1/12
The probability of flipping Heads on a coin is 1 - a certainty - if the coin is flipped often enough. On a single toss of a fair coin the probability is 1/2.
The probability of flipping a coin 3 times and getting 3 heads is 1/2
Complementary events are events that are the complete opposite. The compliment of event A is everything that is not event A. For example, the complementary event of flipping heads on a coin would be flipping tails. The complementary event of rolling a 1 or a 2 on a six-sided die would be rolling a 3, 4, 5, or 6. (The probability of A compliment is equal to 1 minus the probability of A.)
The probability is 0.375