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Answered 2015-05-03 01:19:24
There are 36 possible combinations. Eleven of them have at least one four in it. That means it is 11 over 36, which is a 30.55% chance.
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the probability of tossing a coin and it landing on head is a 1 in 2 chance the probability of rolling a 5 on a dice is a 1 in 6 chance
The probability of tossing a die and getting three 6's in a row is (1/6)3, or about 0.004630.
The probability of tossing 6 heads in 6 dice is 1 in 26, or 1 in 64, or 0.015625. THe probability of doing that at least once in six trials, then, is 6 in 26, or 6 in 64, or 3 in 32, or 0.09375.
The probability of both dice showing the same number is 1/6 and the probability of different numbers is 5/6.
The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954
The probability of getting at least one prime number in two dice is 3/4.
With one roll of three dice, the probability is 7/8.
There are 36 possibilities when rolling two six sided die. 15 of them result in a prime number (2,3,5,7,11) So the probability is 15 in 36 or a 5 in 12 chance.
If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032
It is (1/2)*(1/6) = 1/12
it depends on how many time you throw the dice. the increase number of your throw, the higher the probability to get 8 that one die is showing a 5. that what my opinion.
"A" is singular, "dice" is plural. One "dice" is a "die". Tossing one six sided die means the odds of the number 1 displaying is 1 out of 6. Tossing two six sided dice means the odds of the number 1 displaying is zero, as at a minimum it will be 1 and 1, or 2.
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
The probability of rolling at least one '1' with six dice is 66.5% [1-(5/6)^6]*100%
Fair dice have a 1/6 probability of showing any one of its numbers on top. This, is a simple example which most people are familiar with. It is therefore a useful way to introduce various concepts related to probability.
The probability is 1 and you do not need Matlab to get that answer - only a little bit of thought.
The probability is 0.6187, approx.
50%. There are three dice; each die has 6 faces.
First probability of getting 2 is one in six: 1/6probability of getting no greater than 4 is two chances in six (must be a 5 or 6): 2/6=1/3so probability = 1/6*1/3= 1/18.
The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.
Assuming normal dice, the answer is 0, since it is impossible to roll a 1 on 2 dice = the least you can get is 1 + 1 = 2.
Depends on how many dice are involved. 1 die 1/6 2 dice 1/3 3 dice 1/2
The probability of rolling a 4 in a die is 1 in 6, or about 0.1667. The probability, then, of rolling a 4 in at least one of two dice rolls is twice that, or 2 in 6, or 0.3333. The probability of rolling a sum of 4 in two dice is 3 in 36, or 1 in 18, or about 0.05556.
The probability of getting a sum of 2 at least once is 0.8155
If they are normal dice, the probability is 0.
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