The answer depends on how many coins were tossed.
The probability of getting two tails when tossing a coin is zero, because the coin can only have one result. If, one the other hand, you toss the coin twice, then the probability of getting two tails is 0.25, i.e. the probability of one tail, 0.5, squared.
There are two sides to the coin, so the probability of getting heads or tails on one flip of the coin is 1/2 or 50%.
If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8
The probability of obtaining 4 tails when a coin is flipped 4 times is: P(4T) = (1/2)4 = 1/16 = 0.0625 Then, the probability of obtaining at least 1 head when a coin is flipped 4 times is: P(at least 1 head) = 1 - 1/16 = 15/16 = 0.9375
50% probablility, or 1/2, that is, a one in two chance.There is an equal chance that the coin will land either heads or tails.
There are 8 possible outcomes when a coin is tossed 3 times. Here they are:1. Heads, Heads, Tails.2. Heads, Tails, Heads.3. Tails, Heads, Heads.4. Heads, Heads, Heads.5. Tails, Tails, Heads.6. Tails, Heads, Tails.7. Heads, Tails, Tails.8. Tails, Tails, Tails.There is only one outcome that is heads, heads, heads, so the probability of three heads coming up in three coin tosses is 1 in 8 or 0.125 for that probability.
Let put the question in an other way : obtaining at least one head is the contrary of obtaining two tails at the same time. The probability to obtain one tail with first coin is 1/2, the probability to obtain one tail with the other is also 1/2, so the probability to obtain one tail on each coin is 1/2x1/2 = 1/4 Thus the probability to obtain at least one head is 1-1/4=3/4
This is one of those cases where it is probably easier to think what is the probability of not doing it, then subtracting that from 1 to get the probability of doing it. To not get at least one head and one tail, you would have to get all heads or all tails. To get all heads, the probability is (1/2)5. To get all tails is the same probability; so double it to get the probability of either of those. 2(1/2)5=1/16. Subtract the 1/16 from 1 to get 15/16. Answer: 15/16
The probability of each coin flip, independently, is 0.5 or 50%. The probability of getting one result (either heads or tails) four times in a row is 0.5 to the fourth power or 0.0625, which equals 6.25%
Assuming that it is a fair coin, the probability is 0.9990
The probability is 0.998
The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256
25% or 0.25 Probability of one tail is 0.50. Since two tails are independent events, the probability is 0.5 x 0.5 = 0.25
one out of 5 or 2 out of 10
There are 2^5 (2*2*2*2*2), or 32, possible outcomes of tossing a coin 5 times. Only one of those outcomes does not contain any tails. This leaves us with 31/32, or 97% chance of at least one toss coming up tails.
A biased probability is one where not every outcome has the same chance of occurring. A biased coin is one where one side, the "heads" or "tails" has a greater probability than the other of showing. A coin which has a centre of gravity closer to the tails side than the heads side would be biased in that heads is more likely to show than tails. The size of coin can have an effect on the probability of heads and tails - during the Royal Institute Christmas lectures in the 1990s demonstrating probability a large version of the pound coin was made to be able to allow the audience to see it being tossed - on the broadcast (and tape) version it landed and stayed on its edge! showing the probability of heads = tails ≠ ½; the probability of heads = probability of tails, but they are actually slightly less than ½ as the coin could land on its edge and stay there - with a standard size coin, if it lands on its edge it takes very little for the centre of gravity to shift outside the base of the edge and for the coin to fall over, but with a very large similar coin (ie one scaled up [proportionally] in lengths) it can take quite a bit before the centre of gravity goes outside the base if it lands on its edge which forces it to fall over (plus there will be a "significant" rise in the centre of gravity to do so, thus favouring stability on an edge which does not exist in the standard, small, sized version of the coin).
The probability of obtaining exactly two heads in three flips of a coin is 0.5x0.5x0.5 (for the probabilities) x3 (for the number of ways it could happen). This is 0.375. However, we are told that at least one is a head, so the probability that we got 3 tails was impossible. This probability is 0.53 or 0.125. To deduct this we need to divide the probability we have by 1-0.125 0.375/(1-0.125) = approximately 0.4286
These are independent one has no bearing on the other
With two flips of a coin you can get two heads, two tails, a head and a tail, or a tail and a head. There are a total of four different possible outcomes, and three of them have at least one head. That's 3 out of 4, or 3/4ths. It's also 0.75 which is the probability of getting at least one head with two flips of a coin. Note that as we use the term probability here, it is zero (no chance it can happen at all), or one (it must happen), or something in between. A probability appears in the form of a fraction or decimal, and has no units attached to it.
Consider a coin toss. The probability of the coin coming up head is 1/2, the probability of the coin coming up tails is 1/2. No matter how many times you flip the coin the probability of any particular toss coming up heads or tails is always 1/2.BUTIf you consider two coins tosses as a set then you have four possible outcomes:first coin heads - second coin heads, first coin heads - second coin tails,first coin tails - second coin heads, first coin tails - second coin tailsfor ease of demonstration lets denote heads as H and tails as Tthe above combination would then be HH,HT,TH,TTthe probability of any one of the combinations would be 1/2 for the first coin and 1/2 for the second coin so all combinations have a probability of 1/4. (1/2x1/2=1/4 I hope you realize.)But, if we don't care which coin is H or T then the two combinations HT and TH are the same and we combined their probabilities into one 1/4+1/4=1/2HH,(HT,TH),TT1/4 1/2 1/4
well it depends on what you are tossing, if its a coin then no. it can be heads too. it would have to be a great coincidence for it to be all tails, but thats why the word probability comes in meaning that there is more than one outcome
1/16There is a one-half probability that any flip will be a tail. The probability that all four are tails is (1/2)*(1/2)*(1/2)*(1/2)=1/16, or 6.25%
The probability of a flipped coin landing heads or tails will always be 50% either way, no matter how many times you flip it.
lets get some facts odds of head on 1 coin 50% or evens odds of no head 50% or evens the possible results vary from 1 coin to 2 coins. 1 coin has 2 results heads or tails 2 coins have 4 results. heads heads, tails tails, tails heads, heads tails. each outcome has a probability of 25%. for the question we remove the heads and tail probability and we have 2 outcomes with heads and one without. so 2 to 1 chance or 33.3333 recuring chance.
3 coins can land in 8 different ways. Only one of these ways is all tails. So the probability of rolling at least one heads is 7/8 = 87.5% .