125/153
The individual probability that a child born will be female is 50% or 0.5.Using this we can calculate the probability that at least one of the children will be female by:calculating the probability that none of the children will be female and then subtracting this from 1.The probability that all the children are male is therefore 0.53 = 0.5 * 0.5 * 0.5 = 0.125.Thus the answer is 1 - 0.125 = 0.875 = 87.5%
In a family with four children, the probability of having four boys is 1 in 16.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of 3 girls out of 4 children is 0.2331
there is a 50% chance that two of them will be girls
1/8
The answer to this is 1 minus the probability that they will have 3 or fewer children. This would happen only if they had a boy as the first, second or third child. The probability they have a boy as first child is 0.5 The probability they have a boy as second is 0.25 The probability they have a boy as third is 0.125 Thus the total probability is 0.875 And so the probability they will have more than three children is 1-0.875 or 0.125
The individual probability that a child born will be female is 50% or 0.5.Using this we can calculate the probability that at least one of the children will be female by:calculating the probability that none of the children will be female and then subtracting this from 1.The probability that all the children are male is therefore 0.53 = 0.5 * 0.5 * 0.5 = 0.125.Thus the answer is 1 - 0.125 = 0.875 = 87.5%
In a family with four children, the probability of having four boys is 1 in 16.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of 3 girls out of 4 children is 0.2331
1 in 64
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability that all three children are boys is approx 0.1381
Since the probability of having a son is about 1/2, the probability of the first 4 children being boys is about (1/2)4.
The probability of a boy is still 0.5 no matter how many prior children there are.
The probability is1 - [Prob(No children) + Prob(1 child, a girl) + Prob(2 children, both girls) + Prob(3 children, all girls) + ...]Not all relevant information is readily available.
We would need to know the number of children in the family to answer this question. For instance, the probability of having no girls in a family of two children would be 1/4 theoretically. In general it is 2-n where n is the number of children.
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.
there is a 50% chance that two of them will be girls