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6/16 = 3/8
The probability that 2 flipped coins both come up heads is 0.52 or 0.25
one fourth
1 chance in 4
If you mean 'at least' 2 heads, the probability is 50%. If you mean exactly 2, the probability is 3/8, or 37.5%. There are 3 independent coin tosses, each of which is equally likely to come up heads or tails. That's a total of 2 * 2 * 2 or 8 possible outcomes (HHH, HHT, HTH, etc.). Of these, 4 include 2 or 3 heads, which is half of 8. Only 3 include exactly 2 heads, so the probability of that is 3/8.
1/2 apex It does not matter what each prior flip's result was. Each flip has a probability of 0.5 heads or tails. Coins do not have "memory".
It is 0.1172
First work out the probability of the first two coins being heads and then the last being tails. This is 1/2 x 1/2 x 1/2 which is 1/8 The next step is to find out how many different orders the coins can come in. In this case there are 3 possible orders (HHT, HTH, and THH). Multiply this by the above probability and you get 3/8. Therefore the probability of getting two heads and one tail is 3/8
The probability would be once in 128 attempts. You don't have to toss seven coins simultaneously. the 7 tosses just have to be independent of one another.
For exactly two; we take the chance that for the first two coins come out heads and the second 2 come out tails. and then we multiply by the number of different possibilities. (i.e it could be the first and third or the first and fourth). so we get .5*.5*.5*.5*6=.375=37.5%if you want 2 or greater. the answer by similar logic is .5625 or 56.25%
10C3(0.5)^10
If it is a fair coin then the probability is 0.5