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53 - 1 or 1 chance in 54 or 0.0185 or 1.85%
i dont get it? --- The probability that the first iPod you select is not defective is 16/20. If you selected a non-defective iPod the first time, there are now 15 non-defective iPods out of 19 remaining. So, the odds that the second you selected is non-defective is 15/19. By similar reasoning, the probability that the third is non-defective (given that the first two weren't defective) is 14/18, and for the fourth iPod, it is 13/17. So the probability that none of the four iPods you selected are defective is: (16/20)*(15/19)*(14/18)*(13/17)=364/969, or approximately 37.6%
Each member of the population has the same probability of being in the sample as any other. Equivalently, any set of members of the given sample size has the same probability of being selected as any other set.
The probability is very close to zero.
Random sampling is a method of selecting a sample where each member of the population has the same probability of being included in the sample. An equivalent statement is that each subset of the population, of the given size, has the same probability of being selected as any other subset of that size.
In a probability sample, each unit has the same probability of being included in the sample. Equivalently, given a sample size, each sample of that size from the population has the same probability of being selected. This is not true for non-probability sampling.
The key feature is that each sample of the given size has the same probability of being selected as the sample. Equivalently, each unit in the population has the same probability of being included in the sample.
Every member in the population has the same probability of being in the sample.Or, equivalently, every set of the given sample size has the same probability of being selected.
The probability of selecting 1 female at random is 4/8 There are now 7 students, 3 of which are female so the probability of selecting another female is 3/7 The probability two randomly selected students are female is (4/8)x(3/7)= 3/14
If it is a fair die and rolled fairly, the two events are independent so that the probability is 1/6.
53 - 1 or 1 chance in 54 or 0.0185 or 1.85%
i dont get it? --- The probability that the first iPod you select is not defective is 16/20. If you selected a non-defective iPod the first time, there are now 15 non-defective iPods out of 19 remaining. So, the odds that the second you selected is non-defective is 15/19. By similar reasoning, the probability that the third is non-defective (given that the first two weren't defective) is 14/18, and for the fourth iPod, it is 13/17. So the probability that none of the four iPods you selected are defective is: (16/20)*(15/19)*(14/18)*(13/17)=364/969, or approximately 37.6%
Each member of the population has the same probability of being in the sample as any other. Equivalently, any set of members of the given sample size has the same probability of being selected as any other set.
It is a variable that can take a number of different values. The probability that it takes a value in any given range is determined by a random process and the value of that probability is given by the probability distribution function.It is a variable that can take a number of different values. The probability that it takes a value in any given range is determined by a random process and the value of that probability is given by the probability distribution function.It is a variable that can take a number of different values. The probability that it takes a value in any given range is determined by a random process and the value of that probability is given by the probability distribution function.It is a variable that can take a number of different values. The probability that it takes a value in any given range is determined by a random process and the value of that probability is given by the probability distribution function.
P(A given B')=[P(A)-P(AnB)]/[1-P(B)].In words: Probability of A given B compliment is equal to the Probability of A minus the Probability of A intersect B, divided by 1 minus the probability of B.
all probabilities smaller than the given probability ("at most") all probabilities larger than the given probability ("at least")
The probability of event A occurring given event B has occurred is an example of conditional probability.