Probability

# What is the question of the problem if rolling a number cube labeled from 1 to 6 and the probability is one half?

There could be many questions:

What is the probability of rolling an even number.

What is the probability of rolling an odd number.

What is the probability of rolling a number less than 4.

What is the probability of rolling a number more than 3.

What is the probability of rolling 1,4, or 6.

Basically it could be any question about the probability of rolling half of the faces.

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## Related Questions

The probability of any event is always a number from 0 to 1, inclusive. It can never be 12.

The probability of rolling a multiple of five on a standard die is 1 in 6, or about 0.1667.The probability of rolling a 10, 15, or higher is zero, because the question implied only one die.

The probability of rolling a six is 1 out of 6, or 1/6. Now, perhaps your question is: If I roll a die 180 times, what is the probability of rolling a six at least once. This is the same as rolling a die 180 times and never once rolling a six. The probability is (5/6)180 which is 5.59 x 10-15.

1/2 - you have a 50-50 chance of rolling an even number (or an odd number for that matter !)

The probability of rolling a 5, based on the information given, is 80/375 or 16/75. Your problem describes a relative frequency approximation of probability.

The probability of rolling a sum of 11 with 2 dice is: P(11) = 1/18.For explanation see answer to question: "What is the probability of rolling 7 or 11 with 2 dice?".Read more: What_is_the_probability_of_rolling_7_or_11_with_2_dice

The probability of 3 specific dice rolls is the probability that each one will happen multiplied together. For instance, the probability of rolling 2 then 6 then 4 is the probability of all of these multiplied together: The probability of rolling 2 is 1/6. The probability of rolling 6 is 1/6. The probability of rolling 4 is 1/6. Multiply these together and we get the total probability as 1/216

The probability of rolling a 7 with 2 dice is 6/36; probability of rolling an 11 is 2/36. Add the two together to find probability of rolling a 7 or 11 which is 8/36 or 2/9.

The probability of rolling the 3 is (1/6).The probability of rolling the 1 is (1/6).The probability of rolling the 3 and then the 1 is (1/6) x (1/6) = (1/36) = about 2.78% (rounded)

If 0 is not one of the faces on the cube, then then probability of rolling a 0 is 0.

The probability of rolling a 2 is 1 in 6. The probability of rolling an even number is 3 in 6. The probability of doing both, on two rolls, is 3 in 36, or 1 in 12.

Probability is a number between 0 and 1. The probability of an event cannot be 12.

The factors of 10 are the numbers that divide 10 evenly: 1, 2, 5 and 10. To answer your question, you have to figure out what the probability of rolling one of these numbers is on a number cube.

There is insufficient information in the question to answer it. You did not specify how many dice were involved. Please restate the question. In the meantime, I will give a generalized answer. If the probability of rolling a straight is n, then the probability of rolling straight three times in a row is n3. For instance, with three dice, the probability of rolling a straight is 1 in 36, neglecting (i.e. allowing for) wrap-around straights, and ignoring (sorry, but the math is too complex and does not serve the answer anyway) the fact that straights can go in either direction. That 1 in 36 is n=0.02778. The probability of doing that 3 times in a row, then, is 0.00002143.

The probability of rolling doubles with two dice is 1 in 6, or about 0.167.

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