There are an infinite number of rational numbers between 1.3 and 1.32 - however, the only number rounded to two decimal places between the two numbers is 1.31.
Yes 13/19 is rational because any number that can be expressed as a fraction is a rational number
-13 is rational and an integer.
132 is an integer and not a fraction. However, it can be expressed in rational form as 132/1. You can then calculate equivalent rational fractions if you multiply both, its numerator and denominator, by any non-zero integer.
There is no such number. Irrational numbers are infinitely dense. Given any number near 13, there are more irrational numbers between that number and 13 than there are rational numbers in all.
Yes
There are infinitely many rational number between 13 and 25. Some examples:13.0000001 13.0000001002 13.0000002
-13 is a rational number
13 is the ratio of 13 to 1 ... nice and rational.
13 is rational
There are an infinite number of rational numbers between any two rational numbers. And 2 and 7 are rational numbers. Here's an example. Take 2 and 7 and find the number halfway between them: (2 + 7)/2 = 9/2, which is rational. Then you can take 9/2 and 2 and find a rational number halfway: 2 + 9/2 = 13/2, then divide by 2 = 13/4. No matter how close the rational numbers become, you can add them together and divide by 2, and the new number will be rational, and be in between the other 2.
-13/12 is a rational number
Yes 13/19 is rational because any number that can be expressed as a fraction is a rational number
13 is the ratio of 13 to 1, so it's rational.
It is a rational number
-13 is rational and an integer.
132 is an integer and not a fraction. However, it can be expressed in rational form as 132/1. You can then calculate equivalent rational fractions if you multiply both, its numerator and denominator, by any non-zero integer.
There is no such number. Irrational numbers are infinitely dense. Given any number near 13, there are more irrational numbers between that number and 13 than there are rational numbers in all.