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Let's call the function f and its integral F. If you evaluate F from point a to point b, you will get the area between f and the x-axis. (The area above the x-axis is positive while the area below is negative.)

For example, let's say f = 9x2. F (the integral) would then equal 3x3 + C. If we want to find the area between the f and the x-axis from x = 1 to x = 3, we could F from 1 to 3:

3(3)3 - 3(1)3 = 78, so we know that the area between the x-axis and f from x = 1 to x = 3 is 78 square units. (It's all positive in this case, since it's all above the x-axis.)

The C in the integral is a constant. It does not matter when you are finding the area under f. If you were to put a number in for C, you would get a function link 3x3 + 7. The derivative if this function is f, so f is the slope, or rate of change, of it's integral. (It doesn't matter what the constant is, since the derivative of a constant is zero. The function 3x3 - 9, for example, has the same derivative.)

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Q: What is the relationship between a function and its integral?
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What is the relation between definite integrals and areas?

Consider the integral of sin x over the interval from 0 to 2pi. In this interval the value of sin x rises from 0 to 1 then falls through 0 to -1 and then rises again to 0. In other words the part of the sin x function between 0 and pi is 'above' the axis and the part between pi and 2pi is 'below' the axis. The value of this integral is zero because although the areas enclosed by the parts of the function between 0 and pi and pi and 2pi are the same the integral of the latter part is negative. The point I am trying to make is that a definite integral gives the area between a function and the horizontal axis but areas below the axis are negative. The integral of sin x over the interval from 0 to pi is 2. The integral of six x over the interval from pi to 2pi is -2.


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We need more information. Is there a limit or integral? The theorem states that the deivitive of an integral of a function is the function


What is the relationship of integral and differential calculus?

We say function F is an anti derivative, or indefinite integral of f if F' = f. Also, if f has an anti-derivative and is integrable on interval [a, b], then the definite integral of f from a to b is equal to F(b) - F(a) Thirdly, Let F(x) be the definite integral of integrable function f from a to x for all x in [a, b] of f, then F is an anti-derivative of f on [a,b] The definition of indefinite integral as anti-derivative, and the relation of definite integral with anti-derivative, we can conclude that integration and differentiation can be considered as two opposite operations.


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I used the integral of the function to calculate the area under the curve.


What is integral zero?

The definite integral of any function identically equal to zero between any two points is zero. Integral is the area under the graph of the given function. Sometimes the terms "integral" or "indefinite integral" are used to refer to the general antiderivative of a function, especially in many textbooks. In this case, the indefinite integral is equal to an arbitrary constant, and it is important to distinguish between these two cases.


Relationship between integral and derivative?

The Derivative is the instantaneous rate of change of a function. An integral is the area under some curve between the intervals of a to b. An integral is like the reverse of the derivative, Derivatives bring functions down a power, integrals bring them up, in-fact indefinite integrals (ones that do not have specifications of the area between a to b) are called anti derivatives.


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The range, usually of a function, is the set of value that the function can take. The integral range is a subset of the range consisting of integer values that the function can take.


What is the second derivative of a function's indefinite integral?

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How can I generate a declining function with constraints on the x and y intercepts so that the integral of the curve is constant?

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