10x+5y = 25 5y = -10x+25 y = -2x+5 Therefore: the slope is -2 and the intercept is 5

If 10x + 6y = 24, y = (24 - 10x)/6 = 4 - (5/3)x. The slope of a line with an equation written in this format is the coefficient of x, therefore -(5/3).

Yes if: y = 10x+5 then the slope is 10 and the y intercept is 5.

The slope is 10 and the y intercept is 5

what is the slope-intercept form of the equation 15y=10x+12

An equals sign seems to be missing. If it is -10x=6y-30 then the slope is -5/3. If it is -10x+6y-30=0 then it is 5/3.

- 10X - 5Y = - 6 add 10X to both sides - 5Y = 10X - 6 divide both sides by - 5 Y = - 2X + 6/5 slope(m) = - 2

10x-5y = 50 -5y = -10x+50 y = 2x-10 which is now in slope intercept form

y = 10x + 14 y-int. = 14 x-int. = -14/10 slope = 10

The slope of this equation is 10 and the y intercept is 150

The first step is to put this in the form, y = mx + b. Because then, m is your slope. So, solving the following for y: 5y - 10x = -15, y = 2x - 3. m = 2 in this case, so your slope is 2.

Y = 10x 10x = 40 y = 40

If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14

If you mean point of (1, 4) and slope of -10 then y = -10x+14

If you mean: 6x+20y = 100 then y = -3/10x+5 whereas the slope is -3/10 and the y intercept is 5

If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14

10x 2x divide 2x equals?

y - 9 = 10(x - 2) or y = 10x - 11

10x and 6y are terms of an algebraic expression

10x + 3 = 15 10x = 15 - 3 10x = 12 x = 1.2

10x - 5 = 2510x = 30x = 3

-10x + 2y = 14 Initial problem (-10x + 2y) + 10x = (14) + 10x add 10x to each side of the equation 2y = 10x + 14 value after the addition (2y)/2 = (10x +14)/2 divide by 2 y = 5x + 7 resultant eqution y = mx + b is the standard form m = 5 and b = 7 via substitution slope of standard formula = m, therefore slope = 5 by definition b is the Y-intercept, therefore Y-intercept is 7 --------------------------------------------------------------------------- Note the Y-intercept is where the line crosses the Y Cartesian coordinate axis at x = 0. therefore it can be calculated as Given y = 5x + 7, and x = 0 then y = 5(0) + 7 y = 0 + 7 y = 7 or in logical terms dialectical analysis Thesis is y = 5x + 7 Antithesis is x = 0 Synthesis is y = 7

If: y = 2x+5/4 and y^2 = 10x Then: y^2 = (2x+5/4)^2 So: 4x^2 +5x +25/16 = 10x Transposing terms: 4x^2 -5x +25/16 = 0 A line is tangent to a curve when the discriminant: b^2 -4ac = 0 Thus: 5^2 -4*4*25/16 = 0 Therefore: y = 2x+1.25 is a tangent to the curve y^2 = 10x

10x = 9x -25 10x -9x = -25 x = -25

5x + 4 = 10x - 5 10x - 5x = 4 + 5 5x = 9 x = 1.8

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