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There is insufficient information in the question to properly answer it. You did not specify how many places and how many 3's there are on the spinner, and you did not specify the set from which you could pick an "a", both of which are necessary pieces of information to calculate probability. Please restate the question.
Well it would really depend on how many sections there are in the spinner and how many 3's and 5's there are.
The probability of spinning the number 3, or any number, is 1/4 or 0.25 since there is 4 numbers total.
If there are four colors on a spinner, then the probability of spinning one particular color is 1 in 4, or 0.25. Also, the probability of spinning one of two particular colors is 2 in 4, or 0.5. Combining these two "unrelated" events simply requires multiplication. The probability, then, of spinning one particular color on one spin, and then spinning one of two particular colors on the next spin is (1 in 4) times (2 in 4), or 2 in 16, or 0.125.
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.
There is insufficient information in the question to properly answer it. You did not specify how many places and how many 3's there are on the spinner, and you did not specify the set from which you could pick an "a", both of which are necessary pieces of information to calculate probability. Please restate the question.
Well it would really depend on how many sections there are in the spinner and how many 3's and 5's there are.
what game are you referring to?
The probability of spinning the number 3, or any number, is 1/4 or 0.25 since there is 4 numbers total.
The answer depends on the shape of the spinner and the numbers on it.
If there are four colors on a spinner, then the probability of spinning one particular color is 1 in 4, or 0.25. Also, the probability of spinning one of two particular colors is 2 in 4, or 0.5. Combining these two "unrelated" events simply requires multiplication. The probability, then, of spinning one particular color on one spin, and then spinning one of two particular colors on the next spin is (1 in 4) times (2 in 4), or 2 in 16, or 0.125.
There are 2 * 6 or 12 outcomes for flipping a coin and spinning a spinner that has 6 different colored sections.
Zero if there is no red. 100% if all are red.
The answer depends on the shape of the spinner.
it will be 7:9
the possibles are end less!!
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.