## Answer

###### Wiki User

###### 08/23/2015

The volume of a pyramidal frustum whose bases are
* n*-sided regular polygons is

where *a*1 and *a*2 are the sides of the two
bases.

Note: cot(**x**) = 1 / tan(**x**)

For example, I was not provided my a's to calculate the volume
my pyramidal octagonal frustrum. I was provided only an overal
width (let overal width = **W**) so I had to calculate a1 with
this equation:

**a1** = **W** * (√2 / (2 + √2))

Then with the given ** h** I solved for the overal
width for the top octagon using trigometry;

Used the same **a1** equation but for **a2**;

Then used this equation to find my volume:

It works, I tried it and proved it with AutoCAD using the command MASSPROP

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