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0.3829 approx.
7
Look in any standard normal distribution table; one is given in the related link. Find the area for 2.43 and 1.52; then take the area for 2.43 and subtract the area for 1.52 and that will be the answer. Therefore, .9925 - .9357 = .0568 = area under the normal distribution curve between z equals 1.52 and z equals 2.43.
It is the Standard Normal distribution.
The answer depends on what population characteristic A measures: whether it is mean, variance, standard deviation, proportion etc. It also depends on the sampling distribution of A.
0.3829 approx.
It is 0.158655, approx.
0.0668 or about 1/15
It is 0.158655 or 0.159 approx.is the anwer 0.8413, -0.3413, -0.1587, 0.1587
1.16/z = -1.16/z * * * * * No! Pr(Z > 1.16) = 0.123 So Pr(-1.16 < Z < 1.16) = 1 - 2*0.123 = 1 - 0.246 = 0.754
2.27%
2.27
0.4846
2.16
7
Look in any standard normal distribution table; one is given in the related link. Find the area for 2.43 and 1.52; then take the area for 2.43 and subtract the area for 1.52 and that will be the answer. Therefore, .9925 - .9357 = .0568 = area under the normal distribution curve between z equals 1.52 and z equals 2.43.
It is the Standard Normal distribution.